bash 在bash中如何替换字符串变量，并将其设置为sed命令
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In bash how to replace string variable, and set it into sed command
提问by mining
in a bash script file, I have set one variable like this:
在 bash 脚本文件中，我设置了一个这样的变量：
current_path=`pwd`
sed -i "1s/.*/working_path='$current_path';/" file1.sh
I want to run this script to replace the first line of file1.shinto working_path='$current_path';, but the current_pathhas the /and in the sedcommand, the /is predefined in sedreplace pattern.
And I have tried this:
我想运行这个脚本来替换file1.shinto的第一行working_path='$current_path';，但是在命令中current_path有/和sed，/是在sed替换模式中预定义的。我试过这个：
current_path1="${current_path/\//\\/}"
the above line, I want to replace the /in variable current_pathinto \/, then input the current_path1into the sedcommand, but also has an error.
上面的行，我想更换/在可变current_path进\/，然后输入current_path1到sed命令，而且还具有一个错误。
Could you give me some advice, please? Thanks.
你能给我一些建议吗？谢谢。
回答by Rafa
Try this.
尝试这个。
sed -i -e "1s@.*@working_path='$current_path';@" file1.sh
Use @instead of /in the substitute command.
使用@，而不是/在替换命令。
回答by glenn Hymanman
You can use different delimiters for the s///command:
您可以为s///命令使用不同的分隔符：
current_path=`pwd`
sed -i "1s|.*|working_path='$current_path';|" file1.sh
But you're not really searching and replacing here,, you want to insert the new line and delete the old line:
但是你并不是真正在这里搜索和替换，你想插入新行并删除旧行：
current_path=`pwd`
sed -i -e "1i\working_path='$current_path)';" -e 1d file1.sh
Are you really changing the first line of a .shfile? Are you deleting the she-bang line?
您真的要更改.sh文件的第一行吗？你要删除she-bang线吗？
回答by Jun Kawai
Please add a '/' to the beginning of pattern string. It replaces all matches of pattern with string.
请在模式字符串的开头添加一个“/”。它用字符串替换模式的所有匹配项。
current_path1="${current_path//\//\\/}"
