C# RESTful WCF服务图片上传问题
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RESTful WCF service image upload problem
提问by jaimie
1 namespace Uploader
2 {
3 using System;
4 using System.IO;
5 using System.ServiceModel;
6 using System.ServiceModel.Description;
7 using System.ServiceModel.Web;
8 using System.Drawing;
9 using System.Drawing.Imaging;
10 using System.Net;
11 using System.Xml;
12
13 [ServiceContract(Namespace = "http://Uploader")]
14 public interface IUploaderService
15 {
16 [OperationContract, WebInvoke(Method = "POST",UriTemplate = "File/{fileName}")]
17 bool UploadFile(string fileName, Stream fileContents);
18 }
19
20 [ServiceBehavior(InstanceContextMode = InstanceContextMode.PerCall)]
21 public class UploaderService : IUploaderService
22 {
23 public bool UploadFile(string fileName, Stream fileContents)
24 {
25 return true;
26 }
27 }
28
29 class Program
30 {
31 static void Main()
32 {
33 var host = new
34 ServiceHost(typeof (UploaderService),
35 new Uri("http://localhost:8080/Uploader"));
36 host.AddServiceEndpoint("Uploader.IUploaderService",
37 new WebHttpBinding(), "").Behaviors.Add(new WebHttpBehavior());
38 try
39 {
40 host.Open();
41 Console.WriteLine(host.BaseAddresses[0].AbsoluteUri + " running.");
42 Console.WriteLine();
43 var uri = "http://localhost:8080/Uploader/file.jpg";
44 var req = WebRequest.Create(uri) as HttpWebRequest;
45 if (req != null)
46 {
47 req.Method = "POST";
48 req.ContentType = "image/jpeg";
49 var reqStream = req.GetRequestStream();
50
51 var imageStream = new MemoryStream();
52 using (var i = Image.FromFile(@"c:\photo.jpg"))
53 i.Save(imageStream, ImageFormat.Jpeg);
54
55 var imageArray = imageStream.ToArray();
56 reqStream.Write(imageArray, 0, imageArray.Length);
57 reqStream.Close();
58 var resp = (HttpWebResponse)req.GetResponse();
59 var r = new XmlTextReader(resp.GetResponseStream());
60 if (r.Read())
61 {
62 Console.WriteLine(r.ReadString());
63 }
64 }
65 Console.WriteLine("Press <ENTER> to quit.");
66 Console.ReadLine();
67 }
68 catch (Exception ex)
69 {
70 Console.WriteLine(ex.Message);
71 Console.ReadKey();
72 }
73 finally
74 {
75 if (host.State == CommunicationState.Faulted)
76 host.Abort();
77 else
78 host.Close();
79 }
80 }
81 }
82 }
83
84
Hi, hope you can help....
你好，希望能帮到你......
I am creating a simple app(maybe webpage) that will have a simple UI and will upload files from an external device, the app/webpage will be started via autorun.inf when the user plugs a device into there PC. The webservice will perform the complex job of linking the file to the management system etc. This will enable the IT illiterate users that can't use file explore to submit files to the the management system...!
我正在创建一个简单的应用程序（可能是网页），它将有一个简单的 UI 并将从外部设备上传文件，当用户将设备插入 PC 时，应用程序/网页将通过 autorun.inf 启动。Web 服务将执行将文件链接到管理系统等的复杂工作。这将使无法使用文件浏览的 IT 文盲用户能够将文件提交到管理系统......！
The problem I have is that my RESTful serivce is giving me a 400 error when the content type is a image/jpeg.. It works fine for text/plain or text/xml (see Blog Post)
我遇到的问题是，当内容类型是图像/jpeg 时，我的 RESTful 服务给了我 400 错误。它适用于 text/plain 或 text/xml（请参阅博客文章）
Thanks J
谢谢 J
采纳答案by bendewey
You can try to override any content-type and upload all files as application/octet-stream, or text/plain using an IOperationBehavior.
您可以尝试覆盖任何内容类型并将所有文件上传为应用程序/八位字节流，或使用 IOperationBehavior 的文本/纯文本。
public class WebContentTypeAttribute : Attribute, IOperationBehavior, IDispatchMessageFormatter
{
private IDispatchMessageFormatter innerFormatter;
public string ContentTypeOverride { get; set; }
public WebContentTypeAttribute(string contentTypeOverride)
{
this.ContentTypeOverride = contentTypeOverride;
}
// IOperationBehavior
public void Validate(OperationDescription operationDescription)
{
}
public void ApplyDispatchBehavior(OperationDescription operationDescription, DispatchOperation dispatchOperation)
{
innerFormatter = dispatchOperation.Formatter;
dispatchOperation.Formatter = this;
}
public void ApplyClientBehavior(OperationDescription operationDescription, ClientOperation clientOperation)
{
}
public void AddBindingParameters(OperationDescription operationDescription, BindingParameterCollection bindingParameters)
{
}
// IDispatchMessageFormatter
public void DeserializeRequest(Message message, object[] parameters)
{
if (message == null)
return;
if (string.IsNullOrEmpty(ContentTypeOverride))
return;
var httpRequest = (HttpRequestMessageProperty)message.Properties[HttpRequestMessageProperty.Name];
httpRequest.Headers["Content-Type"] = ContentTypeOverride;
}
public Message SerializeReply(MessageVersion messageVersion, object[] parameters, object result)
{
return innerFormatter.SerializeReply(messageVersion, parameters, result);
}
}
And you would have to modify your Service contract to look like this one
而且您必须修改您的服务合同，使其看起来像这样
[OperationContract]
[WebInvoke(Method = "POST",UriTemplate = "File/{fileName}")]
[WebContentType("application/octet-stream")]
bool UploadFile(string fileName, Stream fileContents);
Although, if you are uploading from a webpage, wouldn't the data be posted in a multipart/form-data format?
虽然，如果您从网页上传，数据不会以多部分/表单数据格式发布吗？
