在 PHP 中显示数组值
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Display array values in PHP
提问by Thomas
So, I'm working with PHP for the first time and I am trying to retrieve and display the values of an array. After a lot of googling, the only methods I can find for this are print_r, var_dumpor var_export. However, all of these methods return something that looks like this:
所以，我是第一次使用 PHP，我正在尝试检索和显示数组的值。经过大量的谷歌搜索，我能找到的唯一方法是print_r,var_dump或var_export。但是，所有这些方法都返回如下所示的内容：
[a] => apple
[b] => banana
[c] => orange
I can't figure out how to style this outout. I need to strip away the [a] =>part and add commas. I know this must be a pretty straightforward process but I haven't been able to track down any documentation that demonstrates how to do it.
我不知道如何设计这个outout。我需要去掉[a] =>部分并添加逗号。我知道这一定是一个非常简单的过程，但我无法找到任何演示如何执行此操作的文档。
回答by Shakti Singh
回答by j_freyre
You can use implode to return your array with a string separator.
您可以使用内爆返回带有字符串分隔符的数组。
$withComma = implode(",", $array);
echo $withComma;
// Will display apple,banana,orange
回答by DJ.Atomix
<?php $data = array('a'=>'apple','b'=>'banana','c'=>'orange');?>
<pre><?php print_r($data); ?></pre>
Result:
Array
(
[a] => apple
[b] => banana
[c] => orange
)
结果：
数组
（
[a] => 苹果
[b] => 香蕉
[c] => 橙
）
回答by Gaurav
use implode(',', $array);for output as apple,banana,orange
使用implode(',', $array);了作为输出apple,banana,orange
Or
或者
foreach($array as $key => $value)
{
echo $key." is ". $value;
}
回答by JazZ
回答by Kerem Cavusoglu
a simple code snippet that i prepared, hope it will be usefull for you;
我准备的一个简单的代码片段，希望对你有用；
$ages = array("Kerem"=>"35","Ahmet"=>"65","Talip"=>"62","Kamil"=>"60");
reset($ages);
for ($i=0; $i < count($ages); $i++){
echo "Key : " . key($ages) . " Value : " . current($ages) . "<br>";
next($ages);
}
reset($ages);
回答by Stefan Gehrig
Iterate over the array and do whatever you want with the individual values.
遍历数组并对各个值执行任何您想要的操作。
foreach ($array as $key => $value) {
echo $key . ' contains ' . $value . '<br/>';
}
回答by user3243940
you can easily use join()
您可以轻松使用 join()
$fruits = array("apple", "banana", "orange");
print join(" ".$fruits);
回答by Meindert A Jorna dewebmeester
Other option:
其他选择：
$lijst=array(6,4,7,2,1,8,9,5,0,3);
for($i=0;$i<10;$i++){
echo $lijst[$i];
echo "<br>";
}
