javascript 从 Backbone.js 模型中完全删除属性
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Completely remove attribute from Backbone.js model
提问by FrizbeeFanatic14
I am trying to totally remove an attribute from a backbone model. The model is being sent to an API that isn't very flexible, and it will break if I send additional attributes over the ones I'm supposed to send, so I need to remove an attribute so it no longer exists.
我试图从主干模型中完全删除一个属性。模型被发送到一个不是很灵活的 API，如果我发送额外的属性而不是我应该发送的属性，它会中断，所以我需要删除一个属性，使其不再存在。
I tried model.unset, from this question, but when I print out the object the attribute I'm trying to remove is still listed, just with a value of null.
我试过model.unset，从这个问题，但是当我打印出对象时，我试图删除的属性仍然列出，只是值为空。
I need the attribute to be completely gone.
我需要属性完全消失。
My basic structure is:
我的基本结构是：
model.unset("AttrName", "silent");
回答by McGarnagle
The problem is that you're using the parameters for unsetincorrectly. "Silent" should be a part of an options hash, not a separate parameter. This works:
问题是您使用的参数unset不正确。"Silent" 应该是options hash的一部分，而不是单独的参数。这有效：
model.unset("AttrName", { silent: true });
The reason for the strange behavior can be seen from the annotated source:
从注释的来源可以看出奇怪行为的原因：
unset: function(attr, options) {
(options || (options = {})).unset = true;
return this.set(attr, null, options);
},
The unsetmethod assumes that its optionsparameter is an object, and attempts to either create or modify it, then passes it on to the setmethod. If you pass a string instead, then the inadvertent effect of the code is to set the attribute to null, rather than to unset it.
该unset方法假定其options参数是一个对象，并尝试创建或修改它，然后将其传递给该set方法。如果改为传递字符串，则代码的无意影响是将该属性设置为 null，而不是取消设置它。
回答by Tal Bereznitskey
Override the toJSON method of your model and only include the attributes you wish to send.
覆盖模型的 toJSON 方法，只包含您希望发送的属性。
Updated: (added code sample)
更新：（添加代码示例）
When extending the model, add a toJSON function and return an object with the desired attributes:
在扩展模型时，添加一个 toJSON 函数并返回一个具有所需属性的对象：
{
toJSON : function() {
return {
name: this.get('name'),
age: this.get('age'),
phoneNumber: this.get('phoneNumber')
};
}
}
回答by poorman
You might try just building an object with only the properties you want (and sending that):
您可以尝试仅使用您想要的属性构建一个对象（并发送它）：
serializeModel: function() {
return {
email: this.$("#email").val(),
password: this.$("#password").val()
}
}
