list 如何在R中组合两个列表
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/36665492/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
How to combine two lists in R
提问by Rohit Singh
I have two lists:
我有两个清单：
l1 = list(2, 3)
l2 = list(4)
I want a third list:
我想要第三个列表：
list(2, 3, 4).
How can I do it in simple way. Although I can do it in for loop, but I am expecting a one liner answer, or maybe an in-built method.
我怎样才能以简单的方式做到这一点。虽然我可以在 for 循环中做到这一点，但我期待一个单一的答案，或者可能是一个内置的方法。
Actually, I have a list:list(list(2, 3), list(2, 4), list(3, 5), list(3, 7), list(5, 6), list(5, 7), list(6, 7)).
After computing on list(2, 3)and list(2, 4), I want list(2, 3, 4).
实际上，我有一个列表：list(list(2, 3), list(2, 4), list(3, 5), list(3, 7), list(5, 6), list(5, 7), list(6, 7)).
在计算list(2, 3)和之后list(2, 4)，我想要list(2, 3, 4).
回答by Vincent Bonhomme
ccan be used on lists (and not only on vectors):
c可用于列表（不仅限于向量）：
# you have
l1 = list(2, 3)
l2 = list(4)
# you want
list(2, 3, 4)
[[1]]
[1] 2
[[2]]
[1] 3
[[3]]
[1] 4
# you can do
c(l1, l2)
[[1]]
[1] 2
[[2]]
[1] 3
[[3]]
[1] 4
If you have a list of lists, you can do it (perhaps) more comfortably with do.call, eg:
如果您有一个列表列表，您可以（也许）更轻松地使用do.call，例如：
do.call(c, list(l1, l2))
回答by akrun
We can use append
我们可以用 append
append(l1, l2)
It also has arguments to insert element at a particular location.
它还具有在特定位置插入元素的参数。
回答by John Proestakes
I was looking to do the same thing, but to preserve the list as a just an array of strings so I wrote a new code, which from what I've been reading may not be the most efficient but worked for what i needed to do:
我想做同样的事情，但为了将列表保留为一个字符串数组，所以我编写了一个新代码，从我所阅读的内容来看，它可能不是最有效的，但适用于我需要做的事情：
combineListsAsOne <-function(list1, list2){
n <- c()
for(x in list1){
n<-c(n, x)
}
for(y in list2){
n<-c(n, y)
}
return(n)
}
It just creates a new list and adds items from two supplied lists to create one.
它只是创建一个新列表并从两个提供的列表中添加项目以创建一个。
