typescript 如何在angular2的同一控制器内的另一个函数中调用一个函数

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时间:2020-10-21 03:43:08  来源:igfitidea点击:

How to call one function in another function inside same controller in angular2

angulartypescriptionic2ionic3

提问by Mohan Gopi

I am working on login page. What I am trying to do is I have two function in a class validateLogin()and submit(). When clicking the login button my is successfully submitted and I am able to get the username and password.

我正在登录页面上工作。我想要做的是我在一个类中有两个函数validateLogin()submit(). 单击登录按钮时,我已成功提交,并且可以获取用户名和密码。

I am trying to call my validateLogin function in my submit function but I am not able call it my sublime text shows an error on the validateLogin and I am not getting any error in my chrome Browser.

我试图在我的提交函数中调用我的 validateLogin 函数,但我无法调用它,我的 sublime 文本在 validateLogin 上显示了一个错误,我的 chrome 浏览器中没有收到任何错误。

import {Component} from '@angular/core';
import {NavController} from 'ionic-angular';
import {FormBuilder,Validators} from "@angular/common";

@Component({
  templateUrl: 'build/pages/home/home.html'
})

export class HomePage {

    public loginForm: any;
  public commentOnTimeOut: any;

  constructor(private navCtrl: NavController, public form:FormBuilder) {
    this.loginForm = this.form.group({
        "email":["",Validators.required],
        "password":["",Validators.required]
    })
  }

  validateLogin(cb){
    window.setTimeout( () => {
        if (this.loginForm.value.email == 'admin' && this.loginForm.value.password == 'admin123') {
          console.log("invoking If part");
          cb('valid User');
        }
        else {
          console.log("invoking elsePart");
          cb('Invalid User');
        }
    }, 3000);
  }

  submit(){

    console.log(this.loginForm.value);
    console.log(this.loginForm.value.email);
    console.log(this.loginForm.value.password);

    validateLogin(this.loginForm.value.email, this.loginForm.value.password, (response) => {
      console.log(response);
      this.commentOnTimeOut = response;
    })

    this.commentOnTimeOut = "Validating User";
    console.log(this.commentOnTimeOut);
  }  

}

How can i call my function validateLogin in my submit function ?

如何在提交函数中调用我的函数 validateLogin ?

Here is an demo plunkerwhere it works good

这是一个演示 plunker,它运行良好

Error:

错误:

GET http://localhost:8100/build/js/app.bundle.jsin my console.

In my serve i get error like TypeScript error: /home/panini/AutoSparParts/app/pages/home/home.ts(40,5): Error TS2663: Cannot find name 'validateLogin'. Did you mean the instance member 'this.validateLogin'?

在我的控制台中获取http://localhost:8100/build/js/app.bundle.js

在我的服务中,我收到错误消息 TypeScript error: /home/panini/AutoSparParts/app/pages/home/home.ts(40,5): Error TS2663: Cannot find name 'validateLogin'. Did you mean the instance member 'this.validateLogin'?

the above error i am invoking any help

上述错误我正在调用任何帮助

采纳答案by sebaferreras

Since you're working with an instanceof a class, if you want to refer to a property or method inside that instance, you have to add the this.before the property or method name.

既然你用工作实例class,如果你想引用该实例中的属性或方法,你必须添加this.的属性或方法的名称之前。

In my serve i get error like TypeScript error: /home/panini/AutoSparParts/app/pages/home/home.ts(40,5): Error TS2663: Cannot find name 'validateLogin'. Did you mean the instance member 'this.validateLogin'?

在我的服务中,我收到类似 TypeScript 错误的错误:/home/panini/AutoSparParts/app/pages/home/home.ts(40,5):错误 TS2663:找不到名称“validateLogin”。您是说实例成员“this.validateLogin”吗?

That's because if don't add the thisto the validateLoginmethod, a global method with that name will be looked for, and because it's not there, an error is thrown. So your submitmethod should be:

那是因为如果不thisvalidateLogin方法添加,将查找具有该名称的全局方法,并且由于它不存在,因此会引发错误。所以你的submit方法应该是:

submit(){

    console.log(this.loginForm.value);
    console.log(this.loginForm.value.email);
    console.log(this.loginForm.value.password);

    this.validateLogin(this.loginForm.value.email, this.loginForm.value.password, (response) => {
      console.log(response);
      this.commentOnTimeOut = response;
    })

    this.commentOnTimeOut = "Validating User";
    console.log(this.commentOnTimeOut);
  } 


UPDATE:

更新:

yes i try that this. and i get error like TypeScript error: /home/panini/AutoSparParts/app/pages/home/home.ts(40,5): Error TS2346: Supplied parameters do not match any signature of call target.

是的,我试试这个。并且我收到类似 TypeScript error: /home/panini/AutoSparParts/app/pages/home/home.ts(40,5): Error TS2346: Supplied parameters do not match any signature of call target 之类的错误。

That's because your validateLoginmethod expect just a single parameter (the cbparameter) and you're sending three parameters (email, password and the callback).

那是因为您的validateLogin方法只需要一个参数(cb参数),而您要发送三个参数(电子邮件、密码和回调)。

Try by modifying that line like this:

尝试像这样修改该行:

 // New method to handle the response
 processLoginResult(response) {
    console.log(response);
    this.commentOnTimeOut = response;
 }

 submit(){

    console.log(this.loginForm.value);
    console.log(this.loginForm.value.email);
    console.log(this.loginForm.value.password);

    // Instead of calling it with email, password and the callback
    // just send the added method as a callback 
    this.validateLogin(this.processLoginResult);

    this.commentOnTimeOut = "Validating User";
    console.log(this.commentOnTimeOut);
}

回答by Ankit Singh

To access class members you need to use this.before any class member , in your case try this

要访问您需要this.在任何类成员之前使用的类成员,在您的情况下试试这个

this.validateLogin(this.loginForm.value.email, this.loginForm.value.password, (response) => {
   console.log(response);
   this.commentOnTimeOut = response;
})