php 警告:mysqli_error() 需要 1 个参数,0 给定错误

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时间:2020-08-26 03:01:34  来源:igfitidea点击:

Warning: mysqli_error() expects exactly 1 parameter, 0 given error

phpmysqli

提问by Aasim Azam

I get the following error

我收到以下错误

Warning: mysqli_error() expects exactly 1 parameter, 0 given

警告:mysqli_error() 需要 1 个参数,0 给定

The problem is with this line of the code:

问题在于这行代码:

$query = mysqli_query($myConnection, $sqlCommand) or die (mysqli_error()); 

The whole code is

整个代码是

session_start();

require_once "scripts/connect_to_mysql2.php";

//Build Main Navigation menu and gather page data here

$sqlCommand = "SELECT id, linklabel FROM pages ORDER BY pageorder ASC";

$query = mysqli_query($myConnection, $sqlCommand) or die (mysqli_error()); 

$menuDisplay = '';
while ($row = mysqli_fetch_array($query)) { 
    $pid = $row["id"];
    $linklabel = $row["linklabel"];

    $menuDisplay .= '<a href="index.php?pid=' . $pid . '">' . $linklabel . '</a><br />';

} 
mysqli_free_result($query); 

The included file has the following line

包含的文件具有以下行

$myConnection = mysqli_connect("$db_host","$db_username","$db_pass","$db_name") or die ("could not connect to mysql"); with reference to $myConnection, why do I get this error?

回答by Jason

mysqli_error() needs you to pass the connection to the database as a parameter. Documentation here has some helpful examples:

mysqli_error() 需要您将连接作为参数传递给数据库。此处的文档有一些有用的示例:

http://php.net/manual/en/mysqli.error.php

http://php.net/manual/en/mysqli.error.php

Try altering your problem line like so and you should be in good shape:

尝试像这样改变你的问题线,你应该处于良好状态:

$query = mysqli_query($myConnection, $sqlCommand) or die (mysqli_error($myConnection)); 

回答by Aasim Azam

mysqli_errorfunction requires $myConnectionas parameters, that's why you get the warning

mysqli_error函数需要$myConnection作为参数,这就是您收到警告的原因

回答by sicKo

At first, the problem is because you did't put any parameter for mysqli_error. I can see that it has been solved based on the post here. Most probably, the next problem is cause by wrong file path for the included file.. .

一开始,问题是因为你没有为mysqli_error 设置任何参数。我可以看到它已根据此处的帖子解决。很可能,下一个问题是由包含文件的错误文件路径引起的..。

Are you sure this code

你确定这个代码

$myConnection = mysqli_connect("$db_host","$db_username","$db_pass","$db_name") or die ("could not connect to mysql");

is in the 'scripts' folder and your main code file is on the same level as the script folder?

位于“脚本”文件夹中,并且您的主代码文件与脚本文件夹位于同一级别?