Bash 脚本 - 在变量中存储没有空格的查找命令输出
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Bash Script - store find command output without spaces in variable
提问by Vebz
I am looking to automate my xcode projects. It all works fine except the projects name with spaces. I have tried the following commands:
我正在寻找自动化我的 xcode 项目。除了带空格的项目名称外，一切正常。我尝试了以下命令：
output_apps=`find ./ -name "*.app" -print`
output_apps=`find ./ -name "*.app"`
When I run
当我跑
find ./ -name "*.app" -print
without storing into variable, it gives me output as expected as mentioned below:
没有存储到变量中，它给了我预期的输出，如下所述：
.//Ten EU.app
.//Ten Official App EU.app
.//Ten Official App.app
.//Ten.app
However when I store the output of above command in a variable as below
但是，当我将上述命令的输出存储在如下变量中时
output_apps=`find ./ -name "*.app" -print`
and then run the following for loop for get the names
然后运行以下 for 循环以获取名称
for curr_app in $o
do
echo "$curr_app"
done
It shows
表明
.//Ten
EU.app
.//Ten
Official
App
EU.app
.//Ten
Official
App.app
.//Ten.app
How do I maintain the spaces between each output and get the following output?
如何维护每个输出之间的空格并获得以下输出？
Ten EU.app
Ten Official App EU.app
Ten Official App.app
Ten.app
回答by Olaf Dietsche
If you don't need to store the file names in a variable, you can use find -print0in combination with xargs -0. This separates the found entries by NUL bytes instead of newlines. xargsreads these NUL separated values and calls some command with as many arguments as possible.
如果不需要将文件名存储在变量中，则可以find -print0与xargs -0. 这将通过 NUL 字节而不是换行符分隔找到的条目。xargs读取这些 NUL 分隔值并调用一些带有尽可能多参数的命令。
find ./ -name "*.app" -print0 | xargs -0 some-command
If you want, you can limit the number of arguments given to some-commandwith xargs -n 1
如果你愿意，你可以限制给参数的个数some-command与xargs -n 1
find ./ -name "*.app" -print0 | xargs -0 -n 1 some-command
Yet another approach is to read the files with a whileloop
另一种方法是用while循环读取文件
find ./ -name "*.app" -print | while read f; do
some-command "$f"
done
This calls some command with one file at a time. The important point is to enclose the $finto double quotes.
这一次用一个文件调用一些命令。最重要的一点是要封闭$f到双引号。
回答by alinsoar
The file names may contain spaces. You need to ask find to separate them via NULL(\0). Use find -print0.
文件名可能包含空格。您需要通过 find 将它们分开NULL(\0)。使用find -print0.
