php 如何使用 curl 发布数据并根据发布的数据获得响应
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How to post data using curl and get reponse based on posted data
提问by atif
Here is my code to POSTdata:
这是我的POST数据代码：
<?php
$data = array("account" => "1234", "dob" => "30051987", "site" => "mytestsite.com");
$data_string = json_encode($data);
$url = 'http://mydomain.com/curl.php';
$ch = curl_init($url);
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");
curl_setopt($ch, CURLOPT_POSTFIELDS, $data_string);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_HTTPHEADER, array(
'Content-Type: application/json',
'Content-Length: ' . strlen($data_string))
);
$result = curl_exec($ch);
curl_close($ch);
$json_result = json_decode($result, true);
?>
<p>Your confirmation number is: <strong><?php echo $json_result['ConfirmationCode']; ?></strong></p>
Whereas on domain/server curl.phpfile code as under:
而在域/服务器curl.php文件代码如下：
<?php
// header
header("content-type: application/json");
if($_POST):
echo json_encode(array('ConfirmationCode' => 'somecode'));
else:
echo json_encode(array('ConfirmationCode' => 'none'));
endif;
?>
But it always return 'none'. Am I missing something?
但它总是返回'none'。我错过了什么吗？
回答by alwaysLearn
The actual problem is in grabbing it..
真正的问题在于抓住它..
<?php
$data = array("account" => "1234", "dob" => "30051987", "site" => "mytestsite.com");
$data_string = json_encode($data);
$url = 'http://mydomain.com/curl.php';
$ch = curl_init($url);
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");
curl_setopt($ch, CURLOPT_POSTFIELDS, $data_string);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_HTTPHEADER, array(
'Content-Type: application/json',
'Content-Length: ' . strlen($data_string))
);
$result = curl_exec($ch);
curl_close($ch);
echo $result;
//$json_result = json_decode($result, true);
?>
your code for curl.php
你的 curl.php 代码
<?php
$fp = fopen('php://input', 'r');
$rawData = stream_get_contents($fp);
echo "<pre>";
print_r($rawData);
echo "</pre>";
/*if($rawData):
echo json_encode(array('ConfirmationCode' => 'somecode'));;
else:
echo json_encode(array('ConfirmationCode' => 'none'));
endif;*/
?>
Since You are sending the data as raw JSON in the body, it will not populate the $_POST variable
由于您在正文中将数据作为原始 JSON 发送，因此它不会填充 $_POST 变量
Hope this will help you
希望能帮到你
回答by atif
The function on this linkwill work.
此链接上的功能将起作用。
<?php
function post_to_url($url, $data) {
$fields = '';
foreach ($data as $key => $value) {
$fields .= $key . '=' . $value . '&';
}
rtrim($fields, '&');
$post = curl_init();
curl_setopt($post, CURLOPT_URL, $url);
curl_setopt($post, CURLOPT_POST, count($data));
curl_setopt($post, CURLOPT_POSTFIELDS, $fields);
curl_setopt($post, CURLOPT_RETURNTRANSFER, 1);
$result = curl_exec($post);
curl_close($post);
return $result;
}
$data = array(
"name" => "new Name",
"website" => "http://bavotasan.com",
"twitterID" => "bavotasan"
);
$surl = 'http://mydomain.com/curl.php';
echo post_to_url($surl, $data);
?>
Whereas, on curl.php
鉴于，在 curl.php
<?php
file_put_contents('abc.text', "here is my data " . implode('->', $_POST));
if ($_POST['name']):
print_r($_POST['name']);
endif;
?>
回答by Passerby
The "correct" Content-Typeheader for a POST request should be application/x-www-form-urlencoded, but you overrode it with application/json(which is only needed from the server side).
Content-TypePOST 请求的“正确”标头应该是application/x-www-form-urlencoded，但您用 覆盖了它application/json（仅服务器端需要）。
Change your code to below:
将您的代码更改为以下内容：
<?php
$data = array("account" => "1234", "dob" => "30051987", "site" => "mytestsite.com");
$data_string = json_encode($data);
$url = 'http://mydomain.com/curl.php';
$ch = curl_init($url);
curl_setopt($ch, CURLOPT_POST, true); // no need to use custom request method
// ----- METHOD #1: no need to "stringify"
curl_setopt($ch, CURLOPT_POSTFIELDS, $data_array);
// ----- METHOD #2: or if you really like to JOSN-ify
curl_setopt($ch, CURLOPT_POSTFIELDS, array("json"=>$data_string));
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
/* ------ this will be handled by PHP/cURL
curl_setopt($ch, CURLOPT_HTTPHEADER, array(
'Content-Type: application/json',
'Content-Length: ' . strlen($data_string))
);
*/
$result = curl_exec($ch);
curl_close($ch);
$json_result = json_decode($result, true);
?>
