Java 如何在 Spring Restful Webservice 中接受 JSON 输入?

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时间:2020-08-12 22:06:48  来源:igfitidea点击:

How to Accept JSON input in Spring Restful Webservice?

javajsonspringweb-servicesspring-mvc

提问by user2985202

I am having hard time accepting JSON input into my Spring Restful Webservice. Basically my purpose is to accept a JSON and return a zip file. But I am not being able to cross first step itself. Following is the controller code

我很难接受 JSON 输入到我的 Spring Restful Web 服务中。基本上我的目的是接受一个 JSON 并返回一个 zip 文件。但我无法跨过第一步本身。以下是控制器代码

@Controller
@RequestMapping(value = "/request")
public class PasskitController {

@Autowired
@Qualifier("PassManager")
private PassManager pm;

/*headers = { "Accept:application/json" }, 
consumes = MediaType.APPLICATION_JSON_VALUE,*/

@RequestMapping(value = "/createPass", method = RequestMethod.POST,
        consumes = MediaType.APPLICATION_JSON_VALUE,
        produces = MediaType.APPLICATION_OCTET_STREAM_VALUE)
public @ResponseBody ByteArrayOutputStream createGiftPass(
        @RequestBody PassGenerationRequest request) throws IOException {
    System.out.println("in createGiftPass() method");
    String success = "Success";
    ByteArrayOutputStream baos = new ByteArrayOutputStream();
    baos.write(success.getBytes());
    return baos;
}

@RequestMapping(value = "/test", method = RequestMethod.GET, 
        produces = MediaType.TEXT_PLAIN_VALUE)
public @ResponseBody
String test() throws IOException {
    System.out.println("in test() method");
    return "Success";
}
}

I need to map the input JSON into following pojo PassGenerationRequest

我需要将输入 JSON 映射到以下 pojo PassGenerationRequest

@JsonAutoDetect
public class PassGenerationRequest {

private String serialNumber;
private String upc;
private String campaign;
private String merchant;

public String getSerialNumber() {
    return serialNumber;
}

public void setSerialNumber(String serialNumber) {
    this.serialNumber = serialNumber;
}

public String getUpc() {
    return upc;
}

public void setUpc(String upc) {
    this.upc = upc;
}

public String getCampaign() {
    return campaign;
}

public void setCampaign(String campaign) {
    this.campaign = campaign;
}

public String getMerchant() {
    return merchant;
}

public void setMerchant(String merchant) {
    this.merchant = merchant;
}
}

Following are the different HttpMessageConverters configured in spring-servlet.xml

以下是 spring-servlet.xml 中配置的不同 HttpMessageConverters

<bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter">
    <property name="messageConverters">
        <list>
            <ref bean="jsonMessageConverter" />
            <ref bean="byteArrayMessageConverter"/>
            <ref bean="stringMessageConverter"/>
        </list>
    </property>

</bean>

<bean id="jsonMessageConverter" class="org.springframework.http.converter.json.MappingHymansonHttpMessageConverter" >
    <property name="supportedMediaTypes" value="application/json" />
</bean>

<bean id="byteArrayMessageConverter"
    class="org.springframework.http.converter.ByteArrayHttpMessageConverter" >
    <property name="supportedMediaTypes" value="application/octet-stream" />
</bean>

<bean id="stringMessageConverter"
    class="org.springframework.http.converter.StringHttpMessageConverter" >
    <property name="supportedMediaTypes" value="text/plain" />
</bean>

Currently I am getting Content type 'text/plain; charset=UTF-8' not supportedexception.

目前我正在获取内容类型“文本/纯文本;charset=UTF-8' 不支持异常。

If I add the header={"Accept: application/json"}then I get exception saying No handler found for the request "request/createPass"

如果我添加header={"Accept: application/json"}然后我得到异常说没有找到请求“request/createPass”的处理程序

Can anyone please help me out over here?

任何人都可以在这里帮助我吗?

Thanks.

谢谢。

回答by Vidya

Verify your request has Content-Typeset to application/json.

验证您的请求已Content-Type设置为application/json

Acceptdescribes the media type you want to see in the response. You have that set for binary data, so when you provide application/jsoninstead, Spring doesn't see a match.

Accept描述您希望在响应中看到的媒体类型。您已经为二进制数据设置了该设置,因此当您提供时application/json,Spring 看不到匹配项。

回答by HKumar

Make sure Hymanson library are in class path Message converter MappingHymansonHttpMessageConverter is for old Hymanson lib before rel 2 , after rel 2 you need to add MappingHymanson2HttpMessageConverter, Also u can remove annotation method handler with simple "" and with Hymanson lib in class path, it will automatically pick your required message converter.

确保 Hymanson 库在类路径中 消息转换器 MappingHymansonHttpMessageConverter 适用于 rel 2 之前的旧 Hymanson lib,在 rel 2 之后您需要添加 MappingHymanson2HttpMessageConverter,您也可以使用简单的“”和类路径中的 Hymanson lib 删除注释方法处理程序,它将自动选择您需要的消息转换器。

回答by Ghanshyam Saini

use this

用这个

<bean
    class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter">
    <property name="messageConverters">
        <list>
            <ref bean="jsonMessageConverter" />
        </list>
    </property>
</bean>