类型错误：DateTime::__construct() 期望参数 1 是字符串，laravel 中给出的对象
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Type error: DateTime::__construct() expects parameter 1 to be string, object given in laravel
提问by Rashed Hasan
I am trying to get late time. $latetime1 returning correct but $latetime2 not returning same as $latetime1. $systemIntime value format and $inTime value format are the same. But I am getting above error for $latetime2. What should be the correct one, please someone help me. Here is my function bellow -
我正在努力争取迟到。$latetime1 返回正确但 $latetime2 不返回与 $latetime1 相同。$systemIntime 值格式和 $inTime 值格式相同。但是我遇到了 $latetime2 以上的错误。什么应该是正确的，请有人帮助我。这是我的功能波纹管 -
public function update(Request $request, Attendance $attendance)
{
$attendance = Attendance::find($attendance->id);
$inTime = $attendance->intime;
// late time caculate
$systemIntime = DB::table('schools')
->join('users', 'schools.id', '=', 'users.school_id')
->select('schools.intime')
->first();
$latetime1 = (new \DateTime($inTime))->format('H:i:s');
$latetime2 = (new \DateTime($systemIntime))->format('H:i:s');
$late = $latetime1->diff($latetime2);
回答by Alexey Mezenin
You're passing the whole object instead of its property, so change this:
你传递的是整个对象而不是它的属性，所以改变这个：
DateTime($systemIntime)
To:
到：
DateTime($systemIntime->intime)
