Python - 如果字符串包含列表或集合中的单词
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Python - If string contains a word from a list or set
提问by MoJo2015
I have searched quite thoroughly and have not found a suitable answer. I am new to Python/Programming, so I appreciate any advice I can get:
我已经搜索得很彻底，但没有找到合适的答案。我是 Python/编程的新手，所以我很感激我能得到的任何建议：
I am trying to search user input strings for certain key words. For example, we'll say filtering out profanity. From my research, I have been able to make the following dummy example:
我正在尝试搜索某些关键字的用户输入字符串。例如，我们会说过滤掉脏话。根据我的研究，我已经能够制作以下虚拟示例：
Swear = ("curse", "curse", "curse") #Obviously not typing actual swear words, created a set
Userinput = str.lower(input("Tell me about your day: "))
if Userinput in Swear:
print("Quit Cursing!")
else:
print("That sounds great!")
Using the above, if the user enters an exact word form the set as their entire string, it will print "quit cursing"; however, if the user enters "curses" or "I like to say curse" it will print "That sounds great!"
使用上面的方法，如果用户从集合中输入一个确切的单词作为他们的整个字符串，它将打印“quit cursing”；然而，如果用户输入“curses”或“我喜欢说curses”，它会打印“这听起来很棒！”
Ultimately what I need is to be able to search the entire string for a key word, not an exact match of the entire string. Ex: "I went to the park and felt like screaming curses" should return true for a match.
最终我需要的是能够在整个字符串中搜索关键字，而不是整个字符串的完全匹配。例如：“我去了公园，感觉像尖叫着诅咒”应该返回 true 以匹配比赛。
采纳答案by caleb.breckon
Swear = ["curse", "curse", "curse"]
for i in Swear:
if i in Userinput:
print 'Quit Cursing!'
You should read up on the differences between lists and tuples.
回答by Tanveer Alam
Swear = ("curse", "curse", "curse")
Userinput = str.lower(raw_input("Tell me about your day: "))
if any(Userinput.find(s)>=0 for s in Swear):
print("Quit Cursing!")
else:
print("That sounds great!")
Result:
结果：
Tell me about your day: curse
Quit Cursing!
Tell me about your day: cursing
That sounds great!
Tell me about your day: curses
Quit Cursing!
Tell me about your day: I like curse
Quit Cursing!
Using Regular Expression:
使用正则表达式：
Pattern used is r"\bcurse[\w]*".
使用的模式是r"\bcurse[\w]*"。
Swear = ("curse", "curse", "curse")
Userinput = str.lower(raw_input("Tell me about your day: "))
if any(match.group() for match in re.finditer(r"\bcurse[\w]*", Userinput)) :
print("Quit Cursing!")
else:
print("That sounds great!")
finditer(pattern, string, flags=0)
Return an iterator over all non-overlapping matches in the
string. For each match, the iterator returns a match object.
Empty matches are included in the result.
回答by Marcin
You can use sets, if only you want to check the existance of swear words,
你可以使用集合，如果你只想检查脏话的存在，
a_swear_set = set(Swear)
if a_swear_set & set(Userinput.split()):
print("Quit Cursing!")
else:
print("That sounds great!")
