jQuery 回调到 .delay()
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Callback to .delay()
提问by Randomblue
I have an $imagethat I .fadeInand .fadeOut, and then .removeafter .fadeOutcompletes. This is my code:
我有一个$imageI.fadeIn和.fadeOut，然后.remove在.fadeOut完成之后。这是我的代码：
$image
.fadeIn()
.fadeOut(function() {
$(this).remove();
});
I want to add a .delayafter .fadeOut, and .removethe $imageonly once .delayhas completed. I have tried:
我想添加.delay后.fadeOut，并.remove在$image一次.delay完成。我试过了：
$image
.fadeIn()
.fadeOut()
.delay(1000, function() {
$(this).remove();
});
The problem is that .delaydoest notaccept a callback function. How can I .removethe picture as a callback to .delay?
问题是，.delay所行不接受一个回调函数。如何.remove将图片作为回调到.delay？
回答by Frédéric Hamidi
回答by Lapple
You can always do it as:
你总是可以这样做：
$image
.fadeIn()
.fadeOut(function() {
var self = this; // Not sure if setTimeout
// saves the pointer to this
setTimeout(function() {
$(self).remove();
}, 1000)
});
回答by Grant Thomas
To my knowledge, you can just strap the calls on afterthe delay call, like this:
据我所知，您可以在延迟调用之后继续调用，如下所示：
$image
.fadeIn()
.fadeOut()
.delay(1000)
.remove()
});
Such as in the following example from the documentation:
例如在文档中的以下示例中：
$('#foo').slideUp(300).delay(800).fadeIn(400);
The temperament of queued items execution spelled out there also:
排队项目执行的气质也说明了：
...the .delay() method allows us to delay the execution of functions that follow it in the queue. It can be used with the standard effects queue or with a custom queue. Only subsequent events in a queue are delayed; for example this will not delay the no-arguments forms of .show() or .hide() which do not use the effects queue.
....delay() 方法允许我们延迟队列中跟随它的函数的执行。它可以与标准效果队列或自定义队列一起使用。只有队列中的后续事件被延迟；例如，这不会延迟不使用效果队列的 .show() 或 .hide() 的无参数形式。
Read the documentation for further information regarding whichqueue you're delaying, if you have troubles with the default fxqueue you might need to specify one.
阅读文档以获取有关您延迟哪个队列的更多信息，如果您在使用默认fx队列时遇到问题，您可能需要指定一个。
