Android Parcelable 遇到 IOException 写入可序列化对象 getactivity()
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原文地址: http://stackoverflow.com/questions/23142893/
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StackOverFlow
Parcelable encountered IOException writing serializable object getactivity()
提问by user2896762
so I am getting this in logcat:
所以我在 logcat 中得到了这个：
java.lang.RuntimeException: Parcelable encountered IOException writing serializable object (name = com.resources.student_list.Student)
I know this means that my student class is not serializable, but it is, here is my student class:
我知道这意味着我的学生类不可序列化，但确实如此，这是我的学生类：
import java.io.Serializable;
public class Student implements Comparable<Student>, Serializable{
private static final long serialVersionUID = 1L;
private String firstName, lastName;
private DSLL<Grade> gradeList;
public Student() {
firstName = "";
lastName = "";
gradeList = new DSLL<Grade>();
}
public String getFirstName() {
return firstName;
}
public void setFirstName(String firstName) {
this.firstName = firstName;
}
public String getLastName() {
return lastName;
}
public void setLastName(String lastName) {
this.lastName = lastName;
}
public DSLL<Grade> getGradeList() {
return gradeList;
}
public void setGradeList(DSLL<Grade> gradeList) {
this.gradeList = gradeList;
}
public int compareTo(Student arg0) {
return this.lastName.compareTo(arg0.getLastName());
}
}
and this is the code that is using the getIntent() method:
这是使用 getIntent() 方法的代码：
public void onItemClick(AdapterView<?> parent, View viewClicked, int pos,
long id) {
Student clickedStudent = studentList.get(pos);
int position = pos;
Intent intent = new Intent(getActivity().getApplicationContext(), ShowStudentActivity.class);
Log.e("CINTENT","CREATED!!!");
intent.putExtra("clickedStudent",clickedStudent);
intent.putExtra("newStudentList",newStudentList);
intent.putExtra("position",position);
Log.e("putExtra","Passed");
Log.e("Start activity","passed");
startActivity(intent);
}
});
please help me figure out whats wrong with this.
请帮我弄清楚这有什么问题。
here is the whole LogCat:
这是整个 LogCat：
04-17 16:12:28.890: E/AndroidRuntime(22815): FATAL EXCEPTION: main
04-17 16:12:28.890: E/AndroidRuntime(22815): java.lang.RuntimeException: Parcelable encountered IOException writing serializable object (name = com.resources.student_list.Student)
04-17 16:12:28.890: E/AndroidRuntime(22815): at android.os.Parcel.writeSerializable(Parcel.java:1181)
04-17 16:12:28.890: E/AndroidRuntime(22815): at android.os.Parcel.writeValue(Parcel.java:1135)
04-17 16:12:28.890: E/AndroidRuntime(22815): at android.os.Parcel.writeMapInternal(Parcel.java:493)
04-17 16:12:28.890: E/AndroidRuntime(22815): at android.os.Bundle.writeToParcel(Bundle.java:1612)
04-17 16:12:28.890: E/AndroidRuntime(22815): at android.os.Parcel.writeBundle(Parcel.java:507)
04-17 16:12:28.890: E/AndroidRuntime(22815): at android.content.Intent.writeToParcel(Intent.java:6111)
04-17 16:12:28.890: E/AndroidRuntime(22815): at android.app.ActivityManagerProxy.startActivity(ActivityManagerNative.java:1613)
04-17 16:12:28.890: E/AndroidRuntime(22815): at android.app.Instrumentation.execStartActivity(Instrumentation.java:1422)
04-17 16:12:28.890: E/AndroidRuntime(22815): at android.app.Activity.startActivityForResult(Activity.java:3191)
04-17 16:12:28.890: E/AndroidRuntime(22815): at android.support.v4.app.FragmentActivity.startActivityFromFragment(FragmentActivity.java:848)
04-17 16:12:28.890: E/AndroidRuntime(22815): at android.support.v4.app.Fragment.startActivity(Fragment.java:878)
04-17 16:12:28.890: E/AndroidRuntime(22815): at com.example.student_lists.MainActivity$DummySectionFragment.onItemClick(MainActivity.java:477)
04-17 16:12:28.890: E/AndroidRuntime(22815): at android.widget.AdapterView.performItemClick(AdapterView.java:292)
04-17 16:12:28.890: E/AndroidRuntime(22815): at android.widget.AbsListView.performItemClick(AbsListView.java:1058)
04-17 16:12:28.890: E/AndroidRuntime(22815): at android.widget.AbsListView$PerformClick.run(AbsListView.java:2514)
04-17 16:12:28.890: E/AndroidRuntime(22815): at android.widget.AbsListView.run(AbsListView.java:3168)
04-17 16:12:28.890: E/AndroidRuntime(22815): at android.os.Handler.handleCallback(Handler.java:605)
04-17 16:12:28.890: E/AndroidRuntime(22815): at android.os.Handler.dispatchMessage(Handler.java:92)
04-17 16:12:28.890: E/AndroidRuntime(22815): at android.os.Looper.loop(Looper.java:137)
04-17 16:12:28.890: E/AndroidRuntime(22815): at android.app.ActivityThread.main(ActivityThread.java:4447)
04-17 16:12:28.890: E/AndroidRuntime(22815): at java.lang.reflect.Method.invokeNative(Native Method)
04-17 16:12:28.890: E/AndroidRuntime(22815): at java.lang.reflect.Method.invoke(Method.java:511)
04-17 16:12:28.890: E/AndroidRuntime(22815): at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:784)
04-17 16:12:28.890: E/AndroidRuntime(22815): at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:551)
04-17 16:12:28.890: E/AndroidRuntime(22815): at dalvik.system.NativeStart.main(Native Method)
04-17 16:12:28.890: E/AndroidRuntime(22815): Caused by: java.io.NotSerializableException: com.resources.student_list.DSLL$DNode
04-17 16:12:28.890: E/AndroidRuntime(22815): at java.io.ObjectOutputStream.writeNewObject(ObjectOutputStream.java:1364)
04-17 16:12:28.890: E/AndroidRuntime(22815): at java.io.ObjectOutputStream.writeObjectInternal(ObjectOutputStream.java:1671)
04-17 16:12:28.890: E/AndroidRuntime(22815): at java.io.ObjectOutputStream.writeObject(ObjectOutputStream.java:1517)
04-17 16:12:28.890: E/AndroidRuntime(22815): at java.io.ObjectOutputStream.writeObject(ObjectOutputStream.java:1481)
04-17 16:12:28.890: E/AndroidRuntime(22815): at java.io.ObjectOutputStream.writeFieldValues(ObjectOutputStream.java:979)
04-17 16:12:28.890: E/AndroidRuntime(22815): at java.io.ObjectOutputStream.defaultWriteObject(ObjectOutputStream.java:368)
04-17 16:12:28.890: E/AndroidRuntime(22815): at java.io.ObjectOutputStream.writeHierarchy(ObjectOutputStream.java:1074)
04-17 16:12:28.890: E/AndroidRuntime(22815): at java.io.ObjectOutputStream.writeNewObject(ObjectOutputStream.java:1404)
04-17 16:12:28.890: E/AndroidRuntime(22815): at java.io.ObjectOutputStream.writeObjectInternal(ObjectOutputStream.java:1671)
04-17 16:12:28.890: E/AndroidRuntime(22815): at java.io.ObjectOutputStream.writeObject(ObjectOutputStream.java:1517)
04-17 16:12:28.890: E/AndroidRuntime(22815): at java.io.ObjectOutputStream.writeObject(ObjectOutputStream.java:1481)
04-17 16:12:28.890: E/AndroidRuntime(22815): at java.io.ObjectOutputStream.writeFieldValues(ObjectOutputStream.java:979)
04-17 16:12:28.890: E/AndroidRuntime(22815): at java.io.ObjectOutputStream.defaultWriteObject(ObjectOutputStream.java:368)
04-17 16:12:28.890: E/AndroidRuntime(22815): at java.io.ObjectOutputStream.writeHierarchy(ObjectOutputStream.java:1074)
04-17 16:12:28.890: E/AndroidRuntime(22815): at java.io.ObjectOutputStream.writeNewObject(ObjectOutputStream.java:1404)
04-17 16:12:28.890: E/AndroidRuntime(22815): at java.io.ObjectOutputStream.writeObjectInternal(ObjectOutputStream.java:1671)
04-17 16:12:28.890: E/AndroidRuntime(22815): at java.io.ObjectOutputStream.writeObject(ObjectOutputStream.java:1517)
04-17 16:12:28.890: E/AndroidRuntime(22815): at java.io.ObjectOutputStream.writeObject(ObjectOutputStream.java:1481)
04-17 16:12:28.890: E/AndroidRuntime(22815): at android.os.Parcel.writeSerializable(Parcel.java:1176)
回答by CommonsWare
Caused by: java.io.NotSerializableException: com.resources.student_list.DSLL$DNode
Your DSLLclass appears to have a DNodestatic inner class, and DNodeis not Serializable.
您的DSLL类似乎有一个DNode静态内部类，而DNode不是Serializable.
回答by Pankaj Talaviya
Your OneThread Class also should implement Serializable. All the sub classesand inner sub classesmust implements Serializable.
您的 OneThread 类也应该实现 Serializable。所有子类和内部子类都必须实现 Serializable。
this is worked for me...
这对我有用...
回答by Francisco Peters
If you can't make DNode serializable a good solution would be to add "transient" to the variable.
如果您不能使 DNode 可序列化，一个好的解决方案是向变量添加“瞬态”。
Example:
例子：
public static transient DNode dNode = null;
This will ignore the variable when using Intent.putExtra(...).
这将在使用 Intent.putExtra(...) 时忽略该变量。
回答by Sai Gopi N
if you POJO contains any other model inside that should also implements Serializable
如果你的 POJO 包含任何其他也应该实现 Serializable 的模型
回答by Gomez NL
For me this was resolved by making the variable withing the class transient.
对我来说，这是通过使变量具有类瞬态来解决的。
Code before:
之前的代码：
public class UserLocation implements Serializable {
public Location lastKnownLocation;
public UserLocation() {}
}
code after
之后的代码
public class UserLocation implements Serializable {
public transient Location lastKnownLocation;
public UserLocation() {}
}
回答by Sridhar Shanmugam
The exception occurred due to the fact that any of the inner classes or other referenced classes didn't implement the serializable implementation. So make sure that all the referenced classes must implement the serializable implementation.
发生异常的原因是任何内部类或其他引用的类都没有实现可序列化的实现。因此，请确保所有引用的类都必须实现可序列化的实现。
回答by Pavel Aslanov
The problem occurs when your custom class has for property some other class e.g. "Bitmap". What I made is to change the property field from "private Bitmap photo" to "private transient Bitmap photo". However the image is empty after I getIntent() in the receiver activity. Because of this I passed the custom class to the intent and also I've created a byte array from the image and pass it separatly to the intent:
当您的自定义类具有某个其他类（例如“位图”）的属性时，就会出现问题。我所做的是将属性字段从“私有位图照片”更改为“私有瞬态位图照片”。但是，在接收器活动中 getIntent() 后，图像为空。因此，我将自定义类传递给了意图，并且我从图像创建了一个字节数组并将其单独传递给意图：
selectedItem is my custom object and getPlacePhoto is his method to get image. I've already set it before and now I just get it first than convert it and pass it separatly:
selectedItem 是我的自定义对象， getPlacePhoto 是他获取图像的方法。我之前已经设置过，现在我只是先获取它，然后再转换它并单独传递它：
Bitmap image = selectedItem.getPlacePhoto();
image.compress(Bitmap.CompressFormat.PNG, 100, stream);
byte[] byteArray = stream.toByteArray();
Intent intent = new Intent(YourPresentActivity.this,
TheReceiverActivity.class);
intent.putExtra("selectedItem", selectedItem);
intent.putExtra("image", byteArray);
startActivity(intent);
`
`
Then in the receiver activity I get my object and the image as byte array, decode the image and set it to my object as photo property.
然后在接收器活动中，我将我的对象和图像作为字节数组，解码图像并将其设置为我的对象作为 photo 属性。
Intent intent = getIntent();
selectedItem = (ListItem) intent.getSerializableExtra("selectedItem");
byte[] byteArray = getIntent().getByteArrayExtra("image");
Bitmap image = BitmapFactory.decodeByteArray(byteArray, 0,
byteArray.length);
selectedItem.setPhoto(image);
回答by yOshi
the Grade class must also implement Serializable
Grade 类还必须实现 Serializable
public class Grade implements Serializable {
.....your content....
}
回答by Dhruv Raval
I am also phase these error and i am little bit change in modelClass which are implemented Serializable interfacelike:
我也在阶段这些错误，我在实现可序列化接口的模型类中略有变化，例如：
At that Model class also implement Parcelable interfacewith writeToParcel()override method
在该 Model 类中，还使用writeToParcel()覆盖方法实现Parcelable接口
Then just got error to "create creator"so CREATORis write and also create with modelclass contructor with arguments & without arguments..
然后只是在“创建创建者”时出错，因此CREATOR被写入并且还使用带参数和不带参数的模型类构造函数创建..
@Override
public void writeToParcel(Parcel dest, int flags) {
dest.writeString(id);
dest.writeString(name);
}
protected ArtistTrackClass(Parcel in) {
id = in.readString();
name = in.readString();
}
public ArtistTrackClass() {
}
public static final Creator<ArtistTrackClass> CREATOR = new Creator<ArtistTrackClass>() {
@Override
public ArtistTrackClass createFromParcel(Parcel in) {
return new ArtistTrackClass(in);
}
@Override
public ArtistTrackClass[] newArray(int size) {
return new ArtistTrackClass[size];
}
};
Here,
这里，
ArtistTrackClass -> ModelClass
ArtistTrackClass -> ModelClass
Constructor with Parcel arguments "read our attributes"and writeToParcel() is "write our attributes"
带有 Parcel 参数的构造函数“读取我们的属性”，而 writeToParcel() 是“写入我们的属性”
回答by sunil KV
I faced Same issue, the issues was there are some inner classes with the static keyword.After removing the static keyword it started working and also the inner class should implements to Serializable
我遇到了同样的问题，问题是有一些带有 static 关键字的内部类。删除 static 关键字后它开始工作并且内部类应该实现为 Serializable
Issue scenario
问题场景
class A implements Serializable{
class static B{
}
}
Resolved By
解决者
class A implements Serializable{
class B implements Serializable{
}
}
