VBA,在列中搜索特定字符,将字符串提取到该字符

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时间:2020-09-11 21:08:33  来源:igfitidea点击:

VBA, search in column for specific character, extract string upto that character

excelvbaexcel-vba

提问by Kinchit

In a specific column, I want to search for a specific character in cells...say "(" or "/". Once this character is found in a cell, I want to extract the part from the beginning of the string upto the point that this character is found, in the cell adjacent to it.

在特定列中,我想在单元格中搜索特定字符...说“(”或“/”。在单元格中找到该字符后,我想从字符串的开头提取部分点在与它相邻的单元格中找到此字符。

E.g. a few values in the column could look like -

例如,列中的一些值可能看起来像 -

Samsung (india)
Samsung/Dhamal
Blackberry (chikna)
Blackberry/Kala Anda
iPhone - egypt
iPhone 5 * yeda

The output will look like -

输出看起来像 -

Samsung
Samsung
Blackberry
Blackberry
iPhone
iPhone 5

NOTE:The cell values in that specific column, are not static, have no pattern, may contain other special characters as well, are not of a specific length.

注意:该特定列中的单元格值不是静态的,没有模式,也可能包含其他特殊字符,没有特定长度。

回答by chuff

This question is well suited for regular expressions. The following function returns the position of the character preceding the first match of a simple regex pattern in a given string. If no match is found, the function returns the length of the string. The function can be combined with the LEFT function to extract the text preceding the match. (The use of LEFT is necessary because, for the sake of simplicity, this function does not implement submatches.)

这个问题非常适合正则表达式。以下函数返回给定字符串中简单正则表达式模式的第一个匹配项之前的字符的位置。如果未找到匹配项,则该函数返回字符串的长度。该函数可以与 LEFT 函数结合使用以提取匹配项之前的文本。(LEFT 的使用是必要的,因为为了简单起见,这个函数没有实现子匹配。

The following formula would extract the product names in your sample data:

以下公式将提取示例数据中的产品名称:

  =LEFT(A1,regexmatch(A1," \(|\/| -| \*"))

Breaking down the match pattern " \(|\/| -| \*":

打破比赛模式" \(|\/| -| \*"

  " \("  matches a space followed by a left parenthesis 
         [the backslash escapes the "(", a special character in regular expressions] 

  "|"    signifies an alternative pattern to match

  "\/"   matches a forward slash (/)

  " -"   matches a space followed by a dash (-)

  " \*"  matches a space followed by an asterisk (*).

To learn more about regular expressions, see this regular expression tutorial, one of many available on the web.

要了解有关正则表达式的更多信息,请参阅此正则表达式教程,这是网络上提供的众多教程之一。

In order for the function to work, you will need to set a reference to Microsoft VBScript Regular Expressions 5.5. To do this, select Tools/References from the VBA IDE and check this item, which will be well down the long list of references.

为了使该函数工作,您需要设置对 Microsoft VBScript 正则表达式 5.5 的引用。为此,请从 VBA IDE 中选择 Tools/References 并选中此项,该项目将位于长长的参考列表中。

  Function regexMatch(text As String, rePattern As String)
      'Response to SO post 16591260
      'Adapted from code at http://www.macrostash.com/2011/10/08/
      '    simple-regular-expression-tutorial-for-excel-vba/.

      Dim regEx As New VBScript_RegExp_55.RegExp
      Dim matches As Variant

      regEx.pattern = rePattern
      regEx.IgnoreCase = True 'True to ignore case
      regEx.Global = False    'Return just the first match

      If regEx.Test(text) Then
         Set matches = regEx.Execute(text)
         regexMatch = matches(0).FirstIndex
      Else
         regexMatch = Len(text)
      End If

  End Function 

The following subroutine applies the string extraction to each cell in a specified data column and writes the new string to a specified result column. Although it would be possible to just call the function for each cell in the data column, this would incur the overhead of compiling the regular expression (which applies to all cells) each time the function was called. To avoid this overhead, the subroutine splits the match function in to two parts, with the pattern definition outside the loop through the data cells, and the pattern execution inside the loop.

以下子例程将字符串提取应用于指定数据列中的每个单元格,并将新字符串写入指定的结果列。尽管可以只为数据列中的每个单元格调用该函数,但这会导致每次调用该函数时编译正则表达式(适用于所有单元格)的开销。为了避免这种开销,子例程将匹配函数分成两部分,在循环外通过数据单元定义模式,在循环内执行模式。

  Sub SubRegexMatch()
      'Response to SO post 16591260
      'Extracts from string content of each data cell in a specified source
      '   column of the active worksheet the characters to the left of the first
      '   match of a regular expression, and writes the new string to corresponding
      '   rows in a specified result column.
      'Set the regular expression, source column, result column, and first
      '   data row in the "parameters" section
      'Regex match code was adapted from http://www.macrostash.com/2011/10/08/
      '   simple-regular-expression-tutorial-for-excel-vba/

      Dim regEx As New VBScript_RegExp_55.RegExp, _
          matches As Variant, _
          regexMatch As Long     'position of character *just before* match
      Dim srcCol As String, _
          resCol As String
      Dim srcRng As Range, _
          resRng As Range
      Dim firstRow As Long, _
          lastRow As Long
      Dim srcArr As Variant, _
          resArr() As String
      Dim i As Long

      'parameters
      regEx.Pattern = " \(|\/| -| \*"    'regular expression to be matched
      regEx.IgnoreCase = True
      regEx.Global = False               'return only the first match found
      srcCol = "A"                       'source data column
      resCol = "B"                       'result column
      firstRow = 2                       'set to first row with data

      With ActiveSheet
          lastRow = .Cells(Cells.Rows.Count, srcCol).End(xlUp).Row
          Set srcRng = .Range(srcCol & firstRow & ":" & srcCol & lastRow)
          Set resRng = .Range(resCol & firstRow & ":" & resCol & lastRow)
          srcArr = srcRng
          ReDim resArr(1 To lastRow - firstRow + 1)
          For i = 1 To srcRng.Rows.Count
              If regEx.Test(srcArr(i, 1)) Then
                  Set matches = regEx.Execute(srcArr(i, 1))
                  regexMatch = matches(0).FirstIndex
              Else
                  regexMatch = Len(srcArr(i, 1)) 'return length of original string if no match
              End If
              resArr(i) = Left(srcArr(i, 1), regexMatch)
          Next i
          resRng = WorksheetFunction.Transpose(resArr) 'assign result to worksheet
      End With
  End Sub

回答by Alan Waage

Something like this will work:

像这样的事情会起作用:

=IF(FIND("(",A1),LEFT(A1,FIND("(",A1)-1),IF(FIND("\",A1),LEFT(A1,FIND("\",A1)-1),""))

If you have more than just the two characters nest in some more IF statements. There is a limit on how much of this you can do before hitting the iteration limit for Cell functions.

如果在更多 IF 语句中嵌套的不仅仅是两个字符。在达到 Cell 函数的迭代限制之前,您可以执行多少操作是有限制的。

回答by dan

You could use the Split()function. Here is an example:

您可以使用该Split()功能。下面是一个例子:

Dim text as String
Dim splt as Variant

text = "Samsung/Dhamal"
splt = Split(text, "/")
MsgBox splt(0)

Just do the same for any other character you want to split. More on this on MSDN: http://msdn.microsoft.com/fr-fr/library/6x627e5f%28v=vs.80%29.aspx

只需对要拆分的任何其他角色执行相同操作即可。有关 MSDN 的更多信息:http: //msdn.microsoft.com/fr-fr/library/6x627e5f%28v=vs.80%29.aspx

The other (better?) alternative I see would be to use InStr()with Left(). InStr()returns the position of the first match it finds. Then you just have to crop your string. Here is an example:

我看到其他(更好?)替代方法是使用InStr()Left()InStr()返回它找到的第一个匹配项的位置。然后你只需要裁剪你的字符串。下面是一个例子:

Dim text as String
Dim position as Integer

text = "Samsung/Dhamal"
position = InStr(text, "/")

If position > 0 then MsgBox Left(text, position)

http://msdn.microsoft.com/fr-fr/library/8460tsh1%28v=vs.80%29.aspx

http://msdn.microsoft.com/fr-fr/library/8460tsh1%28v=vs.80%29.aspx

回答by Stepan1010

This should work for you:

这应该适合你:

Public Function IsAlphaNumeric(sChr As String) As Boolean
    IsAlphaNumeric = sChr Like "[0-9A-Za-z]"
End Function

Sub LeftUntilNonAlphaNumericChar()
    Dim cell As Range
    Dim Counter As Integer
    Dim NumCharsLeftOfNonAlphaNumChar As Long
    Set colRng = ActiveSheet.Range("A1:A1000") 'specify range

    For Each cell In colRng
        If Len(cell.Text) > 0 Then
            MyString = cell.Value
            For Counter = Len(cell.Text) To Counter Step -1
                If IsAlphaNumeric(cell.Characters(Counter, 1).Text) = False And cell.Characters(Counter, 1).Text <> " " Then
                    cell.Offset(0, 1).Value = Left(cell.Value, Counter - 1)
                End If
            Next
        End If
    Next cell
End Sub

It doesn't remove trailing whitespaces on the end but a simple addition to the sub could change that if you wanted. Good Luck.

它不会删除末尾的尾随空格,但如果您愿意,对 sub 的简单添加可以改变它。祝你好运。

ADDITION:You can get the row of the last cell with data in a column and use that in your range(see below):

ADDITION:你可以得到最后一个单元格的行,并在你的范围内使用它(见下文):

Public Function IsAlphaNumeric(sChr As String) As Boolean
    IsAlphaNumeric = sChr Like "[0-9A-Za-z]"
End Function

Sub LeftUntilNonAlphaNumericChar()
    Dim cell As Range
    Dim Counter As Integer
    Dim NumCharsLeftOfNonAlphaNumChar As Long

    Dim LastRow As Long
    If Application.Version >= 12# Then
        LastRow = ActiveSheet.Range("A1048575").End(xlUp).Row + 1
        'MsgBox "You are using Excel 2007 or greater."
    Else
        LastRow = ActiveSheet.Range("A65535").End(xlUp).Row + 1
        'MsgBox "You are using Excel 2003 or lesser."
    End If
    Set colRng = ActiveSheet.Range("A1:A" & LastRow) 'specify range

    For Each cell In colRng
        If Len(cell.Text) > 0 Then
            MyString = cell.Value
            For Counter = Len(cell.Text) To Counter Step -1
                If IsAlphaNumeric(cell.Characters(Counter, 1).Text) = False And cell.Characters(Counter, 1).Text <> " " Then
                    cell.Offset(0, 1).Value = Left(cell.Value, Counter - 1)
                End If
            Next
        End If
    Next cell
End Sub