JavaScript 新日期()
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JavaScript New Date()
提问by DAK
I have the following JavaScript code but for some reason time is not including minutes:
我有以下 JavaScript 代码，但由于某种原因，时间不包括分钟：
var austDay = $("#<%= hiddenFieldTime.ClientID %>").val().split(" ");
var year = austDay[0];
var months = austDay[1];
var days = austDay[2];
var time = austDay[3];
var timeUntil = new Date(parseInt(year), parseInt(months),
parseInt(days), parseInt(time));
When I debug using firebug these are my value:
当我使用 firebug 进行调试时，这些是我的价值：
$("#ctl00_hiddenFieldTime").val() = "2011, 5, 6, 14:20:00"
year = "2011,"
months = "5,"
days = "6,"
time = "14:20:00"
timeUntil = Date {Mon Jun 06 2011 14:00:00 GMT-0400 (Eastern Daylight Time)}
As you can see, timeUntil is set to 14:00:00instead of 14:20:00
如您所见， timeUntil 设置为14:00:00而不是14:20:00
回答by niksvp
parseInt(time)is the problem
parseInt(time)是问题
Here are the few dates initialization format
这是几个日期初始化格式
var d = new Date();
var d = new Date(milliseconds);
var d = new Date(dateString);
var d = new Date(year, month, day, hours, minutes, seconds, milliseconds);
回答by Justin Ethier
According to the Mozilla documentation for Date, the following constructors are supported:
根据Date的Mozilla 文档，支持以下构造函数：
new Date()
new Date(milliseconds)
new Date(dateString)
new Date(year, month, day [, hour, minute, second, millisecond ])
This means that in your constructor, when you pass parseInt(time), that parameter is only used for the hourparameter. You need to pass a separate parameter for minutes, and yet another one if you happen to want seconds.
这意味着在您的构造函数中，当您传递 时parseInt(time)，该参数仅用于该hour参数。您需要为分钟传递一个单独的参数，如果您碰巧需要几秒钟，则需要传递另一个参数。
此外，您应该始终将
basebase参数传递给parseIntparseInt，如下所示：parseInt(hours, 10)
Otherwise when you go to parse a value with a leading 0such as parseInt('08'), the value will be interpreted as an octal number.
否则，当您解析带有0诸如 之类的前导parseInt('08')值时，该值将被解释为八进制数。
回答by davin
Your last conversion is going to drop everything after the colon:
您的最后一次转换将删除冒号后的所有内容：
parseInt("14:20:00"); // 14
The whole conversion is rather bloated, I suggest trying to format the string initially in a format you can pass as isto JS's Dateconstructor, which will make life easier.
整个转换相当臃肿，我建议尝试以一种可以按原样传递给 JSDate构造函数的格式来格式化字符串，这将使生活更轻松。
回答by Headshota
parseInt ("14:20:00")returns 14
parseInt ("14:20:00")返回 14
