ios 为 NSString 的整个长度生成 NSRange 的快捷方式？
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原文地址: http://stackoverflow.com/questions/15062458/
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Shortcut to generate an NSRange for entire length of NSString?
提问by Basil Bourque
Is there a short way to say "entire string" rather than typing out:
有没有一种简短的方法可以说“整个字符串”而不是输入：
NSMakeRange(0, myString.length)]
It seems silly that the longest part of this kind of code is the least important (because I usually want to search/replace within entire string)…
这种代码中最长的部分是最不重要的，这似乎很愚蠢（因为我通常想在整个字符串中搜索/替换）......
[myString replaceOccurrencesOfString:@"replace_me"
withString:replacementString
options:NSCaseInsensitiveSearch
range:NSMakeRange(0, myString.length)];
采纳答案by jscs
Function? Category method?
功能？分类方法？
- (NSRange)fullRange
{
return (NSRange){0, [self length]};
}
[myString replaceOccurrencesOfString:@"replace_me"
withString:replacementString
options:NSCaseInsensitiveSearch
range:[myString fullRange]];
回答by BJ Homer
Not that I know of. But you could easily add an NSStringcategory:
从来没听说过。但是您可以轻松添加一个NSString类别：
@interface NSString (MyRangeExtensions)
- (NSRange)fullRange
@end
@implementation NSString (MyRangeExtensions)
- (NSRange)fullRange {
return (NSRange){0, self.length};
}
回答by SwiftArchitect
Swift
迅速
NSMakeRange(0, str.length)
or as an extension:
或作为extension：
extension NSString {
func fullrange() -> NSRange {
return NSMakeRange(0, self.length)
}
}
回答by vadian
Swift 4+, useful for NSRegularExpressionand NSAttributedString
Swift 4+，适用于NSRegularExpression和NSAttributedString
extension String {
var nsRange : NSRange {
return NSRange(self.startIndex..., in: self)
}
}
回答by Odrakir
This is not shorter, but... Oh well
这不是更短，而是......哦，好吧
NSRange range = [str rangeOfString:str];
回答by Chris Conover
Swift 2:
斯威夫特 2：
extension String {
var fullRange:Range<String.Index> { return startIndex..<endIndex }
}
as in
如
let swiftRange = "abc".fullRange
or
或者
let nsRange = "abc".fullRange.toRange
