Java中将字符串转换为数组
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convert String to Array in Java
提问by SuShiS
I have a txt file like this:
我有一个这样的txt文件：
5
1
3
6
9
5
1
3
6
9
I want to read them using java and store all of the numbers into a array.How do I do that? read them in as string and convert to arrray? (how to convert?) the file only contain ints.
我想使用 java 读取它们并将所有数字存储到一个数组中。我该怎么做？将它们作为字符串读入并转换为数组？（如何转换？）该文件仅包含整数。
I tried read them into a string and use this to convert
我尝试将它们读入一个字符串并使用它来转换
static public int[] strToA(String str)
{
int len = str.length();
int[] array = new int[len];
for (int i = 0; i < len; i++)
{
array[i] = Integer.parseInt(str.substring(i,i+1));
}
return array;
}
采纳答案by ch4nd4n
Code would be something like this. This is untested code and may have Syntax errors.
代码将是这样的。这是未经测试的代码，可能有语法错误。
Path file = "yourfile";
// open file
try (InputStream in = Files.newInputStream(file);
BufferedReader reader =
new BufferedReader(new InputStreamReader(in))) {
String line = null;
intArr = new int[10]; // bad code could fail if file has more than 10
int i = 0;
while ((line = reader.readLine()) != null) {
intArr[i++] = Integer.parseInt(line); // parse String to int
}
} catch (IOException x) {
System.err.println(x);
}
To use List instead of array change line
使用 List 而不是数组更改行
intArr = new int[10];
to
到
List intArr = new ArrayList();
Code would be something like
代码将类似于
List intArr = new ArrayList();
while ((line = reader.readLine()) != null) {
intArr.add(Integer.parseInt(line)); // parse String to int
}
回答by Tim
Scanner can help you read your file, and you can use a Listor something else to store the info.
Scanner 可以帮助您阅读您的文件，您可以使用 aList或其他东西来存储信息。
After that, you can use this Listto convert your Array.
之后，您可以使用它List来转换您的Array.
回答by fanzhang
public static Integer[] read2array(String filePath) throws IOException {
List<Integer> result = new ArrayList<Integer>();
RandomAccessFile randomAccessFile = new RandomAccessFile(filePath, "r");
String line = null;
while(null != (line = randomAccessFile.readLine())) {
result.add(new Integer(line));
}
randomAccessFile.close();
return result.toArray(new Integer[result.size()]);
}
