Python 为什么 set_xticks 不设置刻度的标签？
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Why set_xticks doesn't set the labels of ticks?
提问by colinfang
import pylab as plt
x = range(1, 7)
y = (220, 300, 300, 290, 320, 315)
def test(axes):
axes.bar(x,y)
axes.set_xticks(x, [i+100 for i in x])
a = plt.subplot(1,2,1)
test(a)
b = plt.subplot(1,2,2)
test(b)
I am expecting the xlabs as 101, 102 ...However, if i switch to use plt.xticks(x, [i+100 for i in x])and rewrite the function explicitly, it works.
我期待 xlabs101, 102 ...但是，如果我切换到使用plt.xticks(x, [i+100 for i in x])并显式重写该函数，它就可以工作。
采纳答案by Hooked
.set_xticks()on the axes will set the locations and set_xticklabels()will set the displayed text.
.set_xticks()在轴上将设置位置并set_xticklabels()设置显示的文本。
def test(axes):
axes.bar(x,y)
axes.set_xticks(x)
axes.set_xticklabels([i+100 for i in x])
回答by groceryheist
Another function that might be useful, if you don't want labels for every (or even any) tick is axes.tick_params.
如果您不想要每个（甚至任何）刻度的标签，另一个可能有用的函数是axes.tick_params.
def test(axes):
axes.tick_params(axis='x',which='minor',direction='out',bottom=True,length=5)
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