php cURL 请求 URL 中包含空格的 URL .. 该怎么做
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cURL requesting URL with whitespaces in URL.. What to do
提问by Atticus
So I'm trying to curl this URL:
所以我试图卷曲这个 URL：
http://images.fastcompany.com/upload/Screen shot 2011-04-28 at 8.13.21 PM.png
http://images.fastcompany.com/upload/Screen shot 2011-04-28 at 8.13.21 PM.png
URL Encoded it reads as:
URL Encoded 它读作：
http%3A%2F%2Fimages.fastcompany.com%2Fupload%2FScreen+shot+2011-04-28+at+8.13.21+PM.png
http%3A%2F%2Fimages.fastcompany.com%2Fupload%2FScreen+shot+2011-04-28+at+8.13.21+PM.png
However, curl needs it to be decoded into a proper URL obviously.
但是，curl 显然需要将其解码为正确的 URL。
How do i get around this problem? cURL drops off the rest of the string as soon as it reaches any whitespace... :(
我如何解决这个问题？一旦 cURL 到达任何空格，cURL 就会从字符串的其余部分消失...... :(
I should mention I can't wrap the URL with double quotes as it is a variable being posted.
我应该提到我不能用双引号将 URL 括起来，因为它是一个正在发布的变量。
Edit: hahahahaha wowwwwww brainfart.. thanks guys :P
编辑：hahahahaha wowwwwww Brainfart ..谢谢大家：P
回答by Kane Wallmann
Just use str_replace.
只需使用 str_replace。
echo str_replace ( ' ', '%20', 'http://images.fastcompany.com/upload/Screen shot 2011-04-28 at 8.13.21 PM.png' );
回答by Drew
Perhaps try replacing spaces with %20?
也许尝试用%20?
回答by Hoàng V? Tgtt
I use:
我用：
$link = trim($link);
$link = str_replace ( ' ', '%20', $link);
回答by Juanma Menendez
For me just to put the name with spaces between ""worked.
对我来说，只是在“”之间加上空格就行了。
Example
例子
curl --upload-file "001- name - lastName.pdf" https://transfer.sh/ernesto
Notice the use of "" in "001- name - lastName.pdf"
注意“001-name-lastName.pdf”中“”的使用
回答by Mitchell M
Use the str_replace();function. Replace your " "with "%20"
使用该str_replace();功能。替换你" "的"%20"
