php Laravel 保存一对多关系
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Laravel save one to many relationship
提问by flyingL123
I have the following relationships set up in Laravel:
我在 Laravel 中建立了以下关系：
OrderStatus Model
- hasMany('Order')
Order Model
- 'belongsTo('OrderStatus');
The database is set up with an orderstable and an order_statusestable. The orderstable has a field for order_status_id.
数据库设置了一个orders表和一个order_statuses表。该orders表有一个字段为order_status_id。
When I save an Order, I manually set the order_status_idby fetching the appropriate Order Status model, like this:
当我保存订单时，我order_status_id通过获取适当的订单状态模型来手动设置，如下所示：
$status = OrderStatus::where(['name'=>'sample_status'])->firstOrFail();
$order->order_status_id = $status->id;
$order->save();
I'm wondering if there is a built in function to do this rather than setting the order_status_idmanually. I've read about "Attaching a related model", and "Associating Models" in the Laravel docs, but I can't figure out if these fit my use case. I think the issue I'm having is that I'm working directly with the child model (the order), and trying to set it's parent. Is there a function for this?
我想知道是否有内置函数来执行此操作而不是order_status_id手动设置。我在 Laravel 文档中阅读了“附加相关模型”和“关联模型”，但我不知道这些是否适合我的用例。我认为我遇到的问题是我直接使用子模型（订单），并尝试设置它的父模型。有这个功能吗？
回答by lukasgeiter
Sure you can do this:
当然你可以这样做：
$status = OrderStatus::where(['name'=>'sample_status'])->firstOrFail();
$order = new Order;
$order->status()->associate($status);
$order->save();
(status()is the belongsTo relation. You might need to adjust that name)
（status()是belongsTo 关系。您可能需要调整该名称）
回答by Mysteryos
The correct way, to save a relationship for a new related model is as follows:
为新的相关模型保存关系的正确方法如下：
$status = OrderStatus::where(['name'=>'sample_status'])->firstOrFail();
$order = new Order;
$status->order()->save($order);
Documentation link : http://laravel.com/docs/4.2/eloquent#inserting-related-models
文档链接：http: //laravel.com/docs/4.2/eloquent#inserting-related-models
