奇怪的 Groovy/Java 字符串比较行为
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Strange Groovy / Java String comparison behavior
提问by dromodel
Consider the following script:
考虑以下脚本：
def a = new HashSet()
def str1 = "str1"
def str2 = "str2"
def b = "$str1-$str2"
def c = "str1-str2"
println "b: $b"
println "c: $c"
println "b.equals(c): " + (b.equals(c))
println "b == c: " + (b == c)
println "b.compareTo(c): " + (b.compareTo(c))
a.add(b)
println "a.contains(c): " + a.contains(c)
Which has the following output when run with Groovy 1.8 and JDK 1.6.0_14:
在使用 Groovy 1.8 和 JDK 1.6.0_14 运行时具有以下输出：
b: str1-str2
c: str1-str2
b.equals(c): false
b == c: true
b.compareTo(c): 0
a.contains(c): false
The two strings "b" and "c" print the same sequence of characters yet b.equals(c) is false. According to JDK 1.6 manual, the equals() function should return:
两个字符串 "b" 和 "c" 打印相同的字符序列，但 b.equals(c) 为假。根据 JDK 1.6 手册，equals() 函数应该返回：
Compares this string to the specified object. The result is true if and only if the argument is not null and is a String object that represents the same sequence of characters as this object.
将此字符串与指定的对象进行比较。当且仅当参数不为 null 并且是表示与此对象相同的字符序列的 String 对象时，结果才为真。
Why does equals() not return the value as documented and demonstrated above? Strangely, compareTo() returns 0!
为什么 equals() 不返回上面记录和演示的值？奇怪的是， compareTo() 返回 0！
采纳答案by dromodel
The problem is answered on the Groovy GString page. I need to call toString() on the GString.
该问题在Groovy GString 页面上得到了解答。我需要在 GString 上调用 toString()。
