Linux 使用 find 和 -exec {}，有没有办法计算总数？
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Using find with -exec {}, is there a way to count the total?
提问by ethanpil
I am using a command similar to this one:
我正在使用与此类似的命令：
find . -name "*.php" -exec chmod 755 {} \;
Although, I am not using chmod, I am using a different command which I will not list here. This command is working fine. However, there are thousands of files and directories to be operated on, and this operation takes some time. I am wondering if there is a way to display some sort of total when the operation is complete? Perhaps a count of modified files?
虽然我没有使用 chmod，但我使用的是不同的命令，我不会在这里列出。此命令工作正常。但是，要操作的文件和目录数以千计，并且此操作需要一些时间。我想知道是否有办法在操作完成时显示某种总数？也许是修改文件的数量？
The only thing I can think of is simply to do something like:
我唯一能想到的就是做这样的事情：
find . -name "*.php" -exec chmod 755; echo "+"; {} \;
Will that work? At least we can see that something is happening... Anyone have a better suggestion?
那行得通吗？至少我们可以看到正在发生的事情......有人有更好的建议吗？
采纳答案by David W.
This works:
这有效：
$ find . -name "*.php" -exec chmod 755 {} \; -exec /bin/echo {} \; | wc -l
You have to include a second -exec /bin/echofor this to work. If the findcommand has no output, then wchas no input to count lines for.
你必须包括第二个-exec /bin/echo才能工作。如果find命令没有输出，则wc没有输入来计算行数。
回答by Tim
You can chain multiple -execcommands with a single find command. The syntax for that is:
您可以-exec使用单个 find 命令链接多个命令。其语法是：
find . -exec cmd1 \; -exec cmd2 \; -exec cmd3 \;
which in your case would look like this:
在您的情况下，它看起来像这样：
find . -name '*.php' -exec chmod 755 {} \; -exec echo '+' \;
Although you have a few other options for this. You can redirect output to a file:
尽管您对此还有其他一些选择。您可以将输出重定向到文件：
find . -name '*.php' -exec chmod 755 {} \; > logfile.txt
Or, you can use tee, which will allow you to write the output to a logfile, andstill output to the screen. I find this useful, as the continuously-streamed output to the screen lets me know that the command is still running (not crashed or hung), and I still have the log file to refer to later.
或者，您可以使用tee，这将允许您将输出写入日志文件，并且仍然输出到屏幕。我觉得这很有用，因为屏幕上的连续流输出让我知道命令仍在运行（没有崩溃或挂起），而且我还有日志文件供以后参考。
find . -name '*.php' -exec chmod 755 {} \; | tee logfile.txt
wc -l logfile.txt // prints the lines in the file
grep -c '^+$' logfile.txt // prints the lines containing a single '+'
回答by ott--
With the -exec option find will start a subprocess for each file found. You could speed this up by using xargs like find . -name '*.php' | xargs chmod 755- chmod is started only once.
使用 -exec 选项 find 将为找到的每个文件启动一个子进程。您可以通过使用 xargs 来加快速度，例如find . -name '*.php' | xargs chmod 755- chmod 仅启动一次。
回答by James Sumners
回答by user unknown
find . -name "*.php" -exec chmod 755 {} + -printf '.' | wc -c
If you use + instead of ";", find will try to process chmod 755 on many files in parallel.
如果您使用 + 而不是“;”，find 将尝试并行处理许多文件上的 chmod 755。
You can perform additional commands after the first one, here, for example print a dot, and count the dots in the end.
您可以在第一个命令之后执行其他命令，例如打印一个点，并计算最后的点数。
