php 如何将秒转换为时间格式？
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How to convert seconds to time format?
提问by Dewan159
For some reason I convert a time format like: 03:30 to seconds 3*3600 + 30*60, now. I wanna convert it back to its first (same) format up there. How could that be?
出于某种原因，我将时间格式转换为：03:30 to seconds 3*3600 + 30*60, now. 我想将它转换回它的第一个（相同）格式。怎么会这样？
My attempt:
我的尝试：
3*3600 + 30*60 = 12600
12600 / 60 = 210 / 60 = 3.5, floor(3.5) = 3 = hour
Now, what about the minutes?
现在，分钟呢？
Considering the value can be like 19:00 or 02:51.I think you got the picture.
考虑到价值可能就像19:00 or 02:51.我认为你得到了图片。
And by the way, how to convert 2:0 for example to 02:00 using RegEx?
顺便说一下，如何转换 2:0 for example to 02:00 using RegEx?
回答by CyberJunkie
回答by ITroubs
$hours = floor($seconds / 3600);
$mins = floor($seconds / 60 % 60);
$secs = floor($seconds % 60);
If you want to get time format:
如果要获取时间格式：
$timeFormat = sprintf('%02d:%02d:%02d', $hours, $mins, $secs);
回答by Spudley
If the you know the times will be less than an hour, you could just use the date()or $date->format()functions.
如果您知道时间将少于一个小时，您可以使用date()or$date->format()函数。
$minsandsecs = date('i:s',$numberofsecs);
This works because the system epoch time begins at midnight (on 1 Jan 1970, but that's not important for you).
这是有效的，因为系统纪元时间从午夜开始（1970 年 1 月 1 日，但这对您来说并不重要）。
If it's an hour or more but less than a day, you could output it in hours:mins:secs format with `
如果它是一个小时或更长时间但不到一天，您可以使用 `hours:mins:secs 格式输出它
$hoursminsandsecs = date('H:i:s',$numberofsecs);
For more than a day, you'll need to use modulus to calculate the number of days, as this is where the start date of the epoch would become relevant.
对于超过一天的时间，您需要使用模数来计算天数，因为这是时代的开始日期变得相关的地方。
Hope that helps.
希望有帮助。
回答by marco_manti
Maybe the simplest way is:
也许最简单的方法是：
gmdate('H:i:s', $your_time_in_seconds);
回答by Hammerite
Let $timebe the time as number of seconds.
让$time时间作为秒数。
$seconds = $time % 60;
$time = ($time - $seconds) / 60;
$minutes = $time % 60;
$hours = ($time - $minutes) / 60;
Now the hours, minutes and seconds are in $hours, $minutesand $secondsrespectively.
现在的小时，分钟和秒都在$hours，$minutes和$seconds分别。
回答by GZipp
Another solution that will give you the days, hours, minutes, and seconds for a passed-in seconds value:
另一个解决方案将为您提供传入秒值的天数、小时数、分钟数和秒数：
function seconds_to_time($secs)
{
$dt = new DateTime('@' . $secs, new DateTimeZone('UTC'));
return array('days' => $dt->format('z'),
'hours' => $dt->format('G'),
'minutes' => $dt->format('i'),
'seconds' => $dt->format('s'));
}
print_r(seconds_to_time($seconds_value);
Extra logic will be needed for 'days' if the time is expected to be more than one year. Use str_pad()or ltrim()to add/remove leading zeros.
回答by Flaxious
ITroubs answer doesn't deal with the left over seconds when you want to use this code to convert an amount of seconds to a time format like hours : minutes : seconds
当您想使用此代码将秒数转换为时间格式时，ITroubs 的答案不会处理剩余的秒数： hours : minutes : seconds
Here is what I did to deal with this: (This also adds a leading zero to one-digit minutes and seconds)
这是我为解决这个问题所做的：（这还将前导零添加到一位数的分钟和秒）
$seconds = 3921; //example
$hours = floor($seconds / 3600);
$mins = floor(($seconds - $hours*3600) / 60);
$s = $seconds - ($hours*3600 + $mins*60);
$mins = ($mins<10?"0".$mins:"".$mins);
$s = ($s<10?"0".$s:"".$s);
$time = ($hours>0?$hours.":":"").$mins.":".$s;
$time will contain "1:05:21" in this example.
在此示例中，$time 将包含“1:05:21”。
回答by Julijan An?eli?
If you were to hardcode it you would use modulus to extract the time as others suggested.
如果您要对其进行硬编码，则可以按照其他人的建议使用模数来提取时间。
If you are returning the seconds from MySQL database, assuming you don't need the data in seconds format in your app, there is a much cleaner way to do it, you can use MySQL's SEC_TO_TIMEand it will return time in hh:mm:ss format.
如果您从 MySQL 数据库返回秒数，假设您的应用程序中不需要秒格式的数据，则有一种更简洁的方法，您可以使用 MySQL 的SEC_TO_TIME并且它将以 hh:mm格式返回时间： ss 格式。
Eg.
例如。
SELECT SEC_TO_TIME(my_seconds_field) AS my_timestring;
回答by FatherStorm
something like this?
像这样的东西？
if(is_numeric($time)){
$value = array(
"years" => 0, "days" => 0, "hours" => 0,
"minutes" => 0, "seconds" => 0,
);
if($time >= 31556926){
$value["years"] = floor($time/31556926);
$time = ($time%31556926);
}
if($time >= 86400){
$value["days"] = floor($time/86400);
$time = ($time%86400);
}
if($time >= 3600){
$value["hours"] = floor($time/3600);
$time = ($time%3600);
}
if($time >= 60){
$value["minutes"] = floor($time/60);
$time = ($time%60);
}
$value["seconds"] = floor($time);
return (array) $value;
}else{ return (bool) FALSE; }
}else{ 返回（布尔）假；}
grabbed from: http://www.ckorp.net/sec2time.php
回答by Soroush Khosravi
Sorry this is too late but maybe useful
对不起，这太晚了，但也许有用
function mediaTimeDeFormater($seconds)
{
if (!is_numeric($seconds))
throw new Exception("Invalid Parameter Type!");
$ret = "";
$hours = (string )floor($seconds / 3600);
$secs = (string )$seconds % 60;
$mins = (string )floor(($seconds - ($hours * 3600)) / 60);
if (strlen($hours) == 1)
$hours = "0" . $hours;
if (strlen($secs) == 1)
$secs = "0" . $secs;
if (strlen($mins) == 1)
$mins = "0" . $mins;
if ($hours == 0)
$ret = "$mins:$secs";
else
$ret = "$hours:$mins:$secs";
return $ret;
}
echo mediaTimeDeFormater(216.064000);//3:36
