python wave.readframes 返回什么？
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What is returned by wave.readframes?
提问by Roman
I assign a value to a variable xin the following way:
我x通过以下方式为变量赋值：
import wave
w = wave.open('/usr/share/sounds/ekiga/voicemail.wav', 'r')
x = w.readframes(1)
When I type x I get:
当我输入 x 时，我得到：
'\x1e\x00'
So xgot a value. But what is that? Is it hexadecimal? type(x)and type(x[0])tell me that xand x[0]a strings. Can anybody tell me how should I interpret this strings? Can I transform them into integer?
所以x得到了价值。但那是什么？是十六进制吗？type(x)并type(x[0])告诉我，x和x[0]一个字符串。谁能告诉我应该如何解释这个字符串？我可以将它们转换为整数吗？
回答by AndiDog
The interactive interpreter echoes unprintable characters like that. The string contains two bytes, 0x1E and 0x00. You can convert it to an (WORD-size) integer with struct.unpack("<H", x)(little endian!).
交互式解释器会回显这样的不可打印字符。该字符串包含两个字节，0x1E 和 0x00。您可以使用struct.unpack("<H", x)（小端！）将其转换为（字大小）整数。
回答by Razzad777
Yes, it is in hexadecimal, but what it means depends on the other outputs of the wav file e.g. the sample width and number of channels. Your data could be read in two ways, 2 channels and 1 byte sample width (stereo sound) or 1 channel and 2 byte sample width (mono sound). Use x.getparams(): the first number will be the number of channels and the second will be the sample width.
是的，它是十六进制的，但它的含义取决于 wav 文件的其他输出，例如样本宽度和通道数。您的数据可以通过两种方式读取，2 通道和 1 字节样本宽度（立体声）或 1 通道和 2 字节样本宽度（单声道）。用途x.getparams()：第一个数字是通道数，第二个数字是样本宽度。
This Linkexplains it really well.
这个链接很好地解释了它。
回答by Andrew McGregor
It's a two byte string:
这是一个两字节的字符串：
>>> x='\x1e\x00'
>>> map(ord, list(x))
[30, 0]
>>> [ord(i) for i in x]
[30, 0]
