ios 如何通过点击 Swift 中的按钮打开 fb 和 instagram 应用程序
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How to open fb and instagram app by tapping on button in Swift
提问by Ibrahim
How can I open Facebook and Instagram app by tapping on a button in swift? Some apps redirect to the Facebook app and open a specific page. How can I do the same thing?
如何通过点击中的按钮打开 Facebook 和 Instagram 应用程序swift？某些应用程序重定向到 Facebook 应用程序并打开特定页面。我怎么能做同样的事情？
I found it:
我找到了：
var url = NSURL(string: "itms://itunes.apple.com/de/app/x-gift/id839686104?mt=8&uo=4")
if UIApplication.sharedApplication().canOpenURL(url!) {
UIApplication.sharedApplication().openURL(url!)
}
but I have to know the app URL. Other examples were in ObjectiveC, which I don't know =/
但我必须知道该应用程序URL。其他例子在ObjectiveC，我不知道=/
回答by jregnauld
Take a look at these links, it can help you:
看看这些链接，它可以帮助你：
https://instagram.com/developer/mobile-sharing/iphone-hooks/
https://instagram.com/developer/mobile-sharing/iphone-hooks/
http://wiki.akosma.com/IPhone_URL_Schemes
http://wiki.akosma.com/IPhone_URL_Schemes
Open a facebook link by native Facebook app on iOS
在 iOS 上通过本机 Facebook 应用程序打开 Facebook 链接
Otherwise, there is a quick example with Instagram for opening a specific profile (nickname: johndoe) here:
否则，这里有一个 Instagram 的快速示例，用于打开特定的个人资料（昵称：johndoe）：
var instagramHooks = "instagram://user?username=johndoe"
var instagramUrl = NSURL(string: instagramHooks)
if UIApplication.sharedApplication().canOpenURL(instagramUrl!) {
UIApplication.sharedApplication().openURL(instagramUrl!)
} else {
//redirect to safari because the user doesn't have Instagram
UIApplication.sharedApplication().openURL(NSURL(string: "http://instagram.com/")!)
}
回答by Ibrahim
Update for Swift 4 and iOS 10+
Swift 4 和 iOS 10+ 的更新
OK, there are two easy steps to achieve this in Swift 3:
好的，在 Swift 3 中有两个简单的步骤可以实现这一点：
First, you have to modify Info.plistto list instagramand facebookwith LSApplicationQueriesSchemes. Simply open Info.plistas a Source Code, and paste this:
首先，您必须修改Info.plist为 listinstagram和facebookwith LSApplicationQueriesSchemes。只需Info.plist作为源代码打开，然后粘贴：
<key>LSApplicationQueriesSchemes</key>
<array>
<string>instagram</string>
<string>fb</string>
</array>
After that, you can open instagramand facebookapps by using instagram://and fb://. Here is a complete code for instagram and you can do the same for facebook, you can link this code to any button you have as an Action:
之后，您可以使用和来打开instagram和facebook应用程序。这是 instagram 的完整代码，您可以对 facebook 执行相同的操作，您可以将此代码链接到作为操作的任何按钮：instagram://fb://
@IBAction func InstagramAction() {
let Username = "instagram" // Your Instagram Username here
let appURL = URL(string: "instagram://user?username=\(Username)")!
let application = UIApplication.shared
if application.canOpenURL(appURL) {
application.open(appURL)
} else {
// if Instagram app is not installed, open URL inside Safari
let webURL = URL(string: "https://instagram.com/\(Username)")!
application.open(webURL)
}
}
For facebook, you can use this code:
对于facebook，您可以使用以下代码：
let appURL = URL(string: "fb://profile/\(Username)")!
回答by Celil Bozkurt
In swift 3;
在 swift 3;
First you should add this on your Info.plist
首先，您应该将其添加到您的 Info.plist 中
Than you can use this code;
比您可以使用此代码；
let instagramUrl = URL(string: "instagram://app")
UIApplication.shared.canOpenURL(instagramUrl!)
UIApplication.shared.open(instagramUrl!, options: [:], completionHandler: nil)
回答by DoesData
You actually don't need to use a web and app URL anymore. The web URL will automatically open in the app if the user has it. Instagram or other apps implement this on their end as a Universal Link
您实际上不再需要使用网络和应用程序 URL。如果用户拥有 Web URL，它将在应用程序中自动打开。Instagram 或其他应用程序将其作为通用链接实现
Swift 4
斯威夫特 4
func openInstagram(instagramHandle: String) {
guard let url = URL(string: "https://instagram.com/\(instagramHandle)") else { return }
if UIApplication.shared.canOpenURL(url) {
if #available(iOS 10.0, *) {
UIApplication.shared.open(url, options: [:], completionHandler: nil)
} else {
UIApplication.shared.openURL(url)
}
}
}
回答by Md Imran Choudhury
In swift 4:
在快速 4：
Just change appURLand webURL:
只需更改appURL和webURL：
twitter://user?screen_name=\(screenName)
instagram://user?screen_name=\(screenName)
facebook://user?screen_name=\(screenName)
- 'openURL' was deprecated in iOS 10.0:
- 'openURL' 在 iOS 10.0 中被弃用：
let screenName = "imrankst1221"
let appURL = NSURL(string: "instagram://user?screen_name=\(screenName)")!
let webURL = NSURL(string: "https://twitter.com/\(screenName)")!
if UIApplication.shared.canOpenURL(appURL as URL) {
if #available(iOS 10.0, *) {
UIApplication.shared.open(appURL as URL, options: [:], completionHandler: nil)
} else {
UIApplication.shared.openURL(appURL as URL)
}
} else {
//redirect to safari because the user doesn't have Instagram
if #available(iOS 10.0, *) {
UIApplication.shared.open(webURL as URL, options: [:], completionHandler: nil)
} else {
UIApplication.shared.openURL(webURL as URL)
}
}
回答by Pomo-J
Based on accepted answer here is the way to do this more elegantly with Swift 4
基于这里接受的答案是使用 Swift 4 更优雅地做到这一点的方法
UIApplication.tryURL([
"instagram://user?username=johndoe", // App
"https://www.instagram.com/johndoe/" // Website if app fails
])
And truly remember to add the scheme to allow the app to open. However even if you forget that instagram will open in Safari.
并真正记住添加方案以允许应用程序打开。但是，即使您忘记了 Instagram 将在 Safari 中打开。
The tryUrl is an extension similar to presented here: https://stackoverflow.com/a/29376811/704803
tryUrl 是类似于此处介绍的扩展：https://stackoverflow.com/a/29376811/704803
回答by Talha Rasool
In swift5, use this
在swift5中，使用这个
guard let instagram = URL(string: "https://www.instagram.com/yourpagename") else { return }
UIApplication.shared.open(instagram)
回答by Jonas Deichelmann
SwiftUI Version
SwiftUI 版本
Add in Info.plist
在 Info.plist 中添加
First, you have to modify Info.plistto list instagramand facebookwith LSApplicationQueriesSchemes. Simply open Info.plistas a Source Code, and paste this:
首先，您必须修改Info.plist为 listinstagram和facebookwith LSApplicationQueriesSchemes。只需Info.plist作为源代码打开，然后粘贴：
<key>LSApplicationQueriesSchemes</key>
<array>
<string>instagram</string>
<string>fb</string>
</array>
When you want to open the Facebook App and direct to a Facebook-Page, use the Page-ID. Here is a Link, where you could find them: https://www.facebook.com/help/1503421039731588
当您想打开 Facebook 应用程序并直接访问 Facebook 主页时，请使用主页 ID。这是一个链接，您可以在其中找到它们：https: //www.facebook.com/help/1503421039731588
Schemes
方案
fb://profile – Open Facebook app to the user's profile ORpages
fb://friends – Open Facebook app to the friends list
fb://notifications – Open Facebook app to the notifications list (NOTE: there appears to be a bug with this URL. The Notifications page opens. However, it's not possible to navigate to anywhere else in the Facebook app)
fb://feed – Open Facebook app to the News Feed
fb://events – Open Facebook app to the Events page
fb://requests – Open Facebook app to the Requests list
fb://notes – Open Facebook app to the Notes page
fb://albums – Open Facebook app to Photo Albums list Source: https://stackoverflow.com/a/10416399/8642838
fb://profile – 打开 Facebook 应用到用户的个人资料或页面
fb://friends – 打开 Facebook 应用到好友列表
fb://notifications – 打开 Facebook 应用到通知列表（注意：此 URL 似乎存在错误。通知页面打开。但是，无法导航到 Facebook 应用中的其他任何位置）
fb://feed – 打开 Facebook 应用到新闻提要
fb://events – 打开 Facebook 应用到活动页面
fb://requests – 打开 Facebook 应用到请求列表
fb://notes – 打开 Facebook 应用到 Notes 页面
fb://albums – 打开 Facebook 应用到相册列表来源：https: //stackoverflow.com/a/10416399/8642838
SwiftUI-Code Version
SwiftUI-代码版本
Button(action: {
let url = URL(string: "fb://profile/<PAGE_ID>")!
let application = UIApplication.shared
// Check if the facebook App is installed
if application.canOpenURL(url) {
application.open(url)
} else {
// If Facebook App is not installed, open Safari with Facebook Link
application.open(URL(string: "https://de-de.facebook.com/apple")!)
}
}, label: {
Text("Facebook")
})
