php 文件上传php，只获取文件名
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File upload php, get only file name
提问by Michael Lau
Is it possible to get the filename of a file, without a complete upload
是否可以在没有完整上传的情况下获取文件的文件名
Meaning after the user chose a file, dont upload that file, just get the filename and save to database?
意思是用户选择文件后，不要上传该文件，只需获取文件名并保存到数据库？
回答by priya786
yes it is possible you can use the code as given below
是的，您可以使用下面给出的代码
$filename=$_FILES['nameofyourfileinput']['name'];
echo $filename;
you can echo the $filename;
你可以回显 $filename;
OR You can use jquery to get this value like
或者你可以使用 jquery 来获取这个值
$('#inputid').change(function(){
var value =$(this).val();
alert(value);
})
回答by user3386779
ya it is possible.You can also do this before uploading the file basename() is enough for extracting name.
是的，这是可能的。您也可以在上传文件 basename() 足以提取名称之前执行此操作。
$next=$pfet['f_name']; //fetched file from database
$next1 = basename($next);
回答by jmoreno
The accepted answer doesn't prevent the file upload, it simply provides a way to get the file name independent of the file contents.
接受的答案不会阻止文件上传，它只是提供了一种获取独立于文件内容的文件名的方法。
Preventing file upload, is best looked at the other way: what enables uploading a file. The answer to that is the enctype attribute on the form tag (multipart/form-data).
防止文件上传，最好以另一种方式看待：什么可以上传文件。 答案是表单标签 (multipart/form-data) 上的 enctype 属性。
回答by Carlo Galliano
HTML:
HTML：
<form action="upload.php" method="post" enctype="application/x-www-form-urlencoded">
Select:
<input name="upload[]" type="file" multiple="multiple" />
<input type="submit" value="Update" name="submit">
</form>
PHP:
PHP：
$total = count($_POST['upload']);
// Loop through each file
for( $i=0 ; $i < $total ; $i++ ) {
$fileName = $_POST['upload'][$i];
}
