php Laravel 5 迁移标识符名称太长

声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow 原文地址: http://stackoverflow.com/questions/30170268/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me): StackOverFlow

提示:将鼠标放在中文语句上可以显示对应的英文。显示中英文
时间:2020-08-25 21:35:46  来源:igfitidea点击:

Laravel 5 migration identifier name too long

phplaraveleloquentlaravel-5

提问by geoffs3310

I am trying to run the following migration:

我正在尝试运行以下迁移:

public function up()
{
    Schema::create('lifestyle_questions', function(Blueprint $table)
    {
        $table->increments('id');
        $table->string('question');
        $table->timestamps();
    });

    Schema::create('lifestyle_question_answers', function(Blueprint $table)
    {
        $table->increments('id');
        $table->integer('lifestyle_question_id')->unsigned();
        $table->foreign('lifestyle_question_id')->references('id')->on('lifestyle_questions');
        $table->string('answer');
        $table->timestamps();
    });

    Schema::create('user_lifestyle_question_answers', function(Blueprint $table)
    {
        $table->integer('user_id')->unsigned();
        $table->foreign('user_id')->references('id')->on('users');
        $table->integer('lifestyle_question_answer_id')->unsigned();
        $table->foreign('lifestyle_question_answer_id')->references('id')->on('lifestyle_question_answers');
    });
}

But I get the following error:

但我收到以下错误:

[Illuminate\Database\QueryException]
SQLSTATE[42000]: Syntax error or access violation: 1059 Identifier name 'user_lifestyle_question_answers_lifestyle_question_answer_id_foreign' is too long (SQL: alter table `user_lifestyle_question_answers` add constraint user_lifestyle_question_answers_lifestyle_question_answer_id_foreign foreign key (`lifestyle_question_answer_id`) references `lifestyle_question_answers` (`id`))

[PDOException]
SQLSTATE[42000]: Syntax error or access violation: 1059 Identifier name 'user_lifestyle_question_answers_lifestyle_question_answer_id_foreign' is too long

回答by Pawel Bieszczad

You can pass a custom index name as the second parameter into the foreign() method. Or just use shorter table/column names.

您可以将自定义索引名称作为第二个参数传递给 foreign() 方法。或者只是使用较短的表/列名称。

So you want to do something like:

所以你想做这样的事情:

public function up()
{
    Schema::create('lifestyle_questions', function(Blueprint $table)
    {
        $table->increments('id');
        $table->string('question');
        $table->timestamps();
    });

    Schema::create('lifestyle_question_answers', function(Blueprint $table)
    {
        $table->increments('id');
        $table->integer('lifestyle_question_id')->unsigned();
        $table->foreign('lifestyle_question_id', 'lq_id_foreign')->references('id')->on('lifestyle_questions');
        $table->string('answer');
        $table->timestamps();
    });

    Schema::create('user_lifestyle_question_answers', function(Blueprint $table)
    {
        $table->integer('user_id')->unsigned();
        $table->foreign('user_id')->references('id')->on('users');
        $table->integer('lifestyle_question_answer_id')->unsigned();
        $table->foreign('lifestyle_question_answer_id', 'lqa_id_foreign')->references('id')->on('lifestyle_question_answers');
    });
}