使用 PHP 显示 Json 数据
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Display Json data using PHP
提问by Arif
I have a json file and I want to display its data in a PHP file. I use the below code but it gives me error.
我有一个 json 文件，我想在 PHP 文件中显示它的数据。我使用下面的代码，但它给了我错误。
$json = file_get_contents('data.json');
$data = json_decode($json);
foreach ($data as $value)
{
echo "$value[1]<br>";
}
data.jsonfile contains data in this format.
data.json文件包含这种格式的数据。
{
"users":[
{"id":"03B7F72C1A522631","user":"[email protected]"},
{"id":"27EB9CE8338083AE","user":"[email protected]"},
{"id":"E27854ABBFF8CD92","user":"[email protected]"}],
"status":
{
"version":"0.9.5.0",
"command":"listusers",
"opf":"json",
"error":false,
"code":0
}
}
I want the Output as
我希望输出为
User ID | User Email
03B7F72C1A522631 | [email protected]
27EB9CE8338083AE | [email protected]
回答by Patato
$json = file_get_contents('data.json');
$data = json_decode($json,true);
$users=$data['users'];
for($users as $user)
{
echo $user['id']." ".$user['user'];
}
$status=$data['status'];
回答by Suvash sarker
Use this which will give an associative array instead of an object
使用它会给出一个关联数组而不是一个对象
$data = json_decode($json,true);
for details have a look here json_decode function
详情请看这里json_decode 函数
回答by akshay borase
get data from json file
从json文件中获取数据
$homepage = file_get_contents('url');
$someArray = json_decode($homepage, true);
foreach ($someArray as $key => $value) {
echo "\nAddress: " . $value["address"] . "\n\n";
}
