windows 如何以编程方式更改文件的创建、修改、访问日期？
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How do I programmatically change the create, modify, access date on a file?
提问by Keng
I need to change the modify date on a file on Windows so that it doesn't clutter up my sort order. How can I do that with a script (I may need to do that to the file in the future as well)?
我需要更改 Windows 上文件的修改日期，以免它弄乱我的排序顺序。我怎样才能用脚本来做到这一点（我将来可能也需要对文件这样做）？
BTW: I don't want to have to install applications to do this.
顺便说一句：我不想安装应用程序来做到这一点。
回答by Learning
If you have PowerShell:
如果您有 PowerShell：
$(Get-Item ).creationtime=$(Get-Date "mm/dd/yyyy hh:mm am/pm")
$(Get-Item ).lastaccesstime=$(Get-Date "mm/dd/yyyy hh:mm am/pm")
$(Get-Item ).lastwritetime=$(Get-Date "mm/dd/yyyy hh:mm am/pm")
Note that the correct date format string to use will depend on your localization, e.g. in the UK, the correct format string would be dd/mm/yyyy.
请注意，要使用的正确日期格式字符串将取决于您的本地化，例如在英国，正确的格式字符串为dd/mm/yyyy.
回答by Mark G
Using PowerShell, the command would be:
使用 PowerShell，命令将是：
PS C:\temp> (Get-Item Notes.txt).lastwritetime=$(Get-Date "1/2/2016 12:34 am")
PS C:\temp> (Get-Item Notes.txt).creationtime=$(Get-Date "1/2/2016 12:34 am")
PS C:\temp> (Get-Item Notes.txt).lastaccesstime=$(Get-Date "1/2/2016 12:34 am")
回答by user1016765
In PowerShell you can list the file and use that to set attributes on it in a single line.
在 PowerShell 中，您可以列出文件并使用它在一行中设置属性。
For example with wildcard:
例如使用通配符：
(ls yourF*).lastWriteTime = (get-date).AddDays(-60)
For a single file:
对于单个文件：
(ls yourFile.doc).creationTime = (get-date).AddDays(-60)
(The above commands assume you have cd'd to the file's directory.)
（以上命令假设您已 cd 到文件目录。）
回答by EBGreen
Here is a VBScript example of changing the modification date:
这是更改修改日期的 VBScript 示例：
Sub ChangeModifiedDate(strFolder, strFile, dteNew)
Dim oShell
Dim objFolder
Set oShell = CreateObject("Shell.Application")
Set oFolder = oShell.NameSpace(strFolder)
oFolder.Items.Item(strFile).ModifyDate = dteNew
End Sub
回答by Ido Weinstein
Using Java you can do:
使用 Java，您可以执行以下操作：
File file = new File("someFile");
file.setLastModified(long time);
