如何在 Laravel 中执行 MYSQL 查询？
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How to execute MYSQL query in laravel?
提问by Makerz
I have one MYSQL query with me I want to execute this query in laravel.
我有一个 MYSQL 查询，我想在 laravel 中执行这个查询。
select d1.update_id from ( select update_id, count(update_id)
as ct from updates_tags where tag_id in
(67,33,86,55) group by update_id) as d1 where d1.ct=4
Please guide me how do i Do it easily.
请指导我如何轻松做到。
I have one reference with me.... It is not working
我有一个参考....它不起作用
$updateArray = DB::table('updates_tags')
->select('update_id', DB::raw('count(*) as update_id'))
->whereIn('tag_id',$jsontags)
->groupBy('update_id')
->having('update_id','=',count($jsontags))
->lists('update_id');
回答by Tomer Ofer
You can just do a RAW query. like this:
您可以只执行 RAW 查询。像这样：
$sqlQuery = "SELECT d1.update_id FROM...";
$result = DB::select(DB::raw($sqlQuery));
the $result will be an array
$result 将是一个数组
回答by oseintow
change the where('total','=',count($tags)) to having('total','=',count($tags))
改变 where('total','=',count($tags)) to having('total','=',count($tags))
$update = DB::table('tags')
->select('t_id', 'u_id', DB::raw('count(*) as total'))
->whereIn('t_id',$tags)
->groupBy('u_id')
->having('total','=',count($tags))
->lists('u_id');
回答by Juanjo Salvador
In classic PHP, we used to use mysqliconnector. In CodeIgniter, we use ActiveRecords (fully lovely). In Laravel, there is also ActiveRecords for SQL queries.
在经典的 PHP 中，我们曾经使用过mysqli连接器。在 CodeIgniter 中，我们使用 ActiveRecords（非常可爱）。在 Laravel 中，还有用于 SQL 查询的 ActiveRecords。
Checkout the official Laravel docs, query builder is your friend. https://laravel.com/docs/4.2/queries
查看 Laravel 官方文档，查询构建器是您的朋友。https://laravel.com/docs/4.2/queries
