如何从 php 中的用户输入中删除 http、https 和斜杠
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How do I remove http, https and slash from user input in php
提问by Blur
Example user input
示例用户输入
http://domain.com/
http://domain.com/topic/
http://domain.com/topic/cars/
http://www.domain.com/topic/questions/
I want a php function to make the output like
我想要一个 php 函数来使输出像
domain.com
domain.com/topic/
domain.com/topic/cars/
www.domain.com/topic/questions/
Let me know :)
让我知道 ：）
采纳答案by Jacob Relkin
You should use an array of "disallowed" terms and use strposand str_replaceto dynamically remove them from the passed-in URL:
您应该使用一组“不允许的”术语并使用strpos并str_replace从传入的 URL 中动态删除它们：
function remove_http($url) {
$disallowed = array('http://', 'https://');
foreach($disallowed as $d) {
if(strpos($url, $d) === 0) {
return str_replace($d, '', $url);
}
}
return $url;
}
回答by
ereg_replaceis now deprecated, so it is better to use:
ereg_replace现在已弃用，因此最好使用：
$url = preg_replace("(^https?://)", "", $url );
This removes either http://or https://
这将删除http://或https://
回答by Madbreaks
I'd suggest using the tools PHP gave you, have a look at parse_url.
我建议使用 PHP 给你的工具，看看parse_url。
<?php
$url = 'http://username:password@hostname/path?arg=value#anchor';
print_r(parse_url($url));
echo parse_url($url, PHP_URL_PATH);
?>
The above example will output:
上面的例子将输出：
Array
(
[scheme] => http
[host] => hostname
[user] => username
[pass] => password
[path] => /path
[query] => arg=value
[fragment] => anchor
)
/path
It sounds like you're after at least host+ path(add others as needed, e.g. query):
听起来您至少在追求host+ path（根据需要添加其他人，例如query）：
$parsed = parse_url('http://www.domain.com/topic/questions/');
echo $parsed['host'], $parsed['path'];
> www.domain.com/topic/questions/
Cheers
干杯
回答by Jordan Casey
Create an array:
创建一个数组：
$remove = array("http://","https://");
$remove = array("http://","https://");
and replace with empty string:
并替换为空字符串：
str_replace($remove,"",$url);
str_replace($remove,"",$url);
it would look something like this:
它看起来像这样：
function removeProtocol($url){
$remove = array("http://","https://");
return str_replace($remove,"",$url);
}
Str_replace will return a string if your haystack (input) is a string and you replace your needle(s) in the array with a string. It's nice so you can avoid all the extra looping.
如果您的 haystack（输入）是字符串并且您用字符串替换数组中的针，则 Str_replace 将返回一个字符串。这很好，因此您可以避免所有额外的循环。
Happy Coding!
快乐编码！
回答by minaz
You can remove both https and http in one line using ereg_replace:
您可以使用 ereg_replace 在一行中同时删除 https 和 http：
$url = ereg_replace("(https?)://", "", $url);
回答by Paul Weber
You could use the parse url Functionality of PHP. This will work for all Protocols, even ftp:// or https://
您可以使用 PHP 的 parse url 功能。这适用于所有协议，甚至 ftp:// 或 https://
Eiter get the Protocol Component and substr it from the Url, or just concatenate the other Parts back together ...
Eiter 获取协议组件并将其从 URL 中删除，或者只是将其他部分连接在一起......
回答by OpenWebWar
<?php
// user input
$url = 'http://www.example.com/category/website/wordpress/wordpress-security/';
$url0 = 'http://www.example.com/';
$url1 = 'http://www.example.com/category/';
$url2 = 'http://www.example.com/category/website/';
$url3 = 'http://www.example.com/category/website/wordpress/';
// print_r(parse_url($url));
// echo parse_url($url, PHP_URL_PATH);
$removeprotocols = array('http://', 'https://');
echo '<br>' . str_replace($removeprotocols,"",$url0);
echo '<br>' . str_replace($removeprotocols,"",$url1);
echo '<br>' . str_replace($removeprotocols,"",$url2);
echo '<br>' . str_replace($removeprotocols,"",$url3);
?>
回答by mike-source
Wow. I came here from google expecting to find a one liner to copy and paste!
哇。我从谷歌来到这里，希望找到一个可以复制和粘贴的衬垫！
You don't need a function to do this because one already exists. Just do:
您不需要一个函数来执行此操作，因为一个函数已经存在。做就是了：
echo explode("//", "https://anyurl.any.tld/any/directory/structure")[1];
In this example, explode() will return an array of:
在这个例子中，explode() 将返回一个数组：
["https:", "anyurl.any.tld/any/directory/structure"]
And we want the 2nd element. This will handle http, https, ftp, or pretty much any URI, without needing regex.
我们想要第二个元素。这将处理 http、https、ftp 或几乎任何 URI，而无需正则表达式。
https://www.php.net/manual/en/function.explode.php
https://www.php.net/manual/en/function.explode.php
If you want a function:
如果你想要一个函数：
function removeProtocols($uri) { return explode("//", $uri)[1]; }
回答by Ives.me
Found this http://refactormycode.com/codes/598-remove-http-from-url-string
发现这个http://refactormycode.com/codes/598-remove-http-from-url-string
function remove_http($url = '')
{
if ($url == 'http://' OR $url == 'https://')
{
return $url;
}
$matches = substr($url, 0, 7);
if ($matches=='http://')
{
$url = substr($url, 7);
}
else
{
$matches = substr($url, 0, 8);
if ($matches=='https://')
$url = substr($url, 8);
}
return $url;
}
回答by Iyad Al aqel
if its the first characters in the string you can use substr(0,8) , and it will remove the first 8th character if its not use the "str_replace()" function http://php.net/manual/en/function.str-replace.php
如果它是字符串中的第一个字符，您可以使用 substr(0,8) ，如果不使用“str_replace()”函数，它将删除第一个第 8 个字符 http://php.net/manual/en/function .str-replace.php
