java LIBGDX：如何使用 shaperenderer 绘制填充多边形？
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LIBGDX: How do I draw a filled polygon with the shaperenderer?
提问by dewijones92
I have defined a shape using an array of vertices:
我已经使用顶点数组定义了一个形状：
float[] points = new float[]{50,60,50,70,60,70, 60,60,50,60};
And I am drawing this here:
我在这里画这个：
shapeRenderer.polygon(floatNew);
This just gives an outline of the shape.
How do I fill it with colour?
Thanks
这只是给出了形状的轮廓。
我如何用颜色填充它？
谢谢
回答by Anubitum
Currently, ShapeRenderer supports polygon drawing (by line) but not filling.
目前，ShapeRenderer 支持多边形绘制（按线），但不支持填充。
This code is clipping the polygon on triangles, and then drawing each triangle separately.
这段代码在三角形上裁剪多边形，然后分别绘制每个三角形。
Edit ShapeRenderer.java like this:
像这样编辑 ShapeRenderer.java：
EarClippingTriangulator ear = new EarClippingTriangulator();
public void polygon(float[] vertices, int offset, int count)
{
if (shapeType != ShapeType.Filled && shapeType != ShapeType.Line)
throw new GdxRuntimeException("Must call begin(ShapeType.Filled) or begin(ShapeType.Line)");
if (count < 6)
throw new IllegalArgumentException("Polygons must contain at least 3 points.");
if (count % 2 != 0)
throw new IllegalArgumentException("Polygons must have an even number of vertices.");
check(shapeType, null, count);
final float firstX = vertices[0];
final float firstY = vertices[1];
if (shapeType == ShapeType.Line)
{
for (int i = offset, n = offset + count; i < n; i += 2)
{
final float x1 = vertices[i];
final float y1 = vertices[i + 1];
final float x2;
final float y2;
if (i + 2 >= count)
{
x2 = firstX;
y2 = firstY;
} else
{
x2 = vertices[i + 2];
y2 = vertices[i + 3];
}
renderer.color(color);
renderer.vertex(x1, y1, 0);
renderer.color(color);
renderer.vertex(x2, y2, 0);
}
} else
{
ShortArray arrRes = ear.computeTriangles(vertices);
for (int i = 0; i < arrRes.size - 2; i = i + 3)
{
float x1 = vertices[arrRes.get(i) * 2];
float y1 = vertices[(arrRes.get(i) * 2) + 1];
float x2 = vertices[(arrRes.get(i + 1)) * 2];
float y2 = vertices[(arrRes.get(i + 1) * 2) + 1];
float x3 = vertices[arrRes.get(i + 2) * 2];
float y3 = vertices[(arrRes.get(i + 2) * 2) + 1];
this.triangle(x1, y1, x2, y2, x3, y3);
}
}
}
回答by BennX
You cant draw a filled Polygon with the shaperender yet. take a look at this from the bugtracker
You can also read that in the API.
你还不能用 shaperender 绘制一个填充的多边形。从bugtracker 中查看此内容
您也可以在 API 中阅读该内容。
public void polygon(float[] vertices)
Draws a polygon in the x/y plane. The vertices must contain at least 3 points (6 floats x,y). The ShapeRenderer.ShapeType passed to begin has to be ShapeRenderer.ShapeType.Line.
public voidpolygon(float[] vertices)
在 x/y 平面上绘制一个多边形。顶点必须至少包含 3 个点（6 个浮点数 x,y）。传递给开始的 ShapeRenderer.ShapeType 必须是 ShapeRenderer.ShapeType.Line。
API ShapeRender
Sure if its with ShapeType.Line you just get the outlines.
You need to draw it yourself with Triangles in that case. It should be possible to fill at least Triangles.
Maybe take a look at this from Stackoverflow: drawing-filled-polygon-with-libgdx
API ShapeRender
当然，如果它与 ShapeType.Line 一起，你就可以得到轮廓。
在这种情况下，您需要自己用三角形绘制它。应该至少可以填充三角形。
也许从 Stackoverflow 看看这个：drawing-filled-polygon-with-libgdx
回答by Sajal Dutta
You should use meshfor that. Take a look at the link. Also, you might want to check PolygonSpriteBatch.
您应该为此使用网格。看看链接。此外，您可能想检查PolygonSpriteBatch。
回答by J Fixby
Edit your ShapeRenderer.java class replacing polygon() method with the following code:
编辑您的 ShapeRenderer.java 类，用以下代码替换多边形（）方法：
public void polygon(float[] vertices, int offset, int count) {
if (currType != ShapeType.Filled && currType != ShapeType.Line)
throw new GdxRuntimeException(
"Must call begin(ShapeType.Filled) or begin(ShapeType.Line)");
if (count < 6)
throw new IllegalArgumentException(
"Polygons must contain at least 3 points.");
if (count % 2 != 0)
throw new IllegalArgumentException(
"Polygons must have an even number of vertices.");
checkDirty();
checkFlush(count);
final float firstX = vertices[0];
final float firstY = vertices[1];
if (currType == ShapeType.Line) {
for (int i = offset, n = offset + count; i < n; i += 2) {
final float x1 = vertices[i];
final float y1 = vertices[i + 1];
final float x2;
final float y2;
if (i + 2 >= count) {
x2 = firstX;
y2 = firstY;
} else {
x2 = vertices[i + 2];
y2 = vertices[i + 3];
}
renderer.color(color);
renderer.vertex(x1, y1, 0);
renderer.color(color);
renderer.vertex(x2, y2, 0);
}
} else {
for (int i = offset, n = offset + count; i < n; i += 4) {
final float x1 = vertices[i];
final float y1 = vertices[i + 1];
if (i + 2 >= count) {
break;
}
final float x2 = vertices[i + 2];
final float y2 = vertices[i + 3];
final float x3;
final float y3;
if (i + 4 >= count) {
x3 = firstX;
y3 = firstY;
} else {
x3 = vertices[i + 4];
y3 = vertices[i + 5];
}
renderer.color(color);
renderer.vertex(x1, y1, 0);
renderer.color(color);
renderer.vertex(x2, y2, 0);
renderer.color(color);
renderer.vertex(x3, y3, 0);
}
}
}
Usage:
用法：
gdx_shape_renderer.begin(ShapeType.Filled);
gdx_shape_renderer.setColor(fill_r, fill_g, fill_b, fill_a);
gdx_shape_renderer.polygon(vertices);
gdx_shape_renderer.end();
gdx_shape_renderer.begin(ShapeType.Line);
gdx_shape_renderer.setColor(border_r, border_g, border_b, border_a);
gdx_shape_renderer.polygon(vertices);
gdx_shape_renderer.end();
