如何使用 Java 正则表达式替换 URL 中的所有特殊字符？
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How can I replace all special characters in a URL, using a Java regular expression?
提问by Shamik
I'm trying use regular expression to convert special characters in an url. Here's my sample code :
我正在尝试使用正则表达式来转换 url 中的特殊字符。这是我的示例代码：
String formatUrl = "index.php?title=Test/enu/test/Tips_%26_Tricks/Tips_and_Tricks";
formatUrl = formatUrl.replaceAll("[^a-zA-Z0-9]" , "-");
What I'm trying to do is to convert the special characters in the url such as ?_%. to "-" excluding "/".
我想要做的是转换 url 中的特殊字符，例如 ?_%。到“-”，不包括“/”。
The regular expression in my code converts everything resulting the output as
我的代码中的正则表达式将导致输出的所有内容转换为
index-php-title-Test-enu-test-Tips--26-Tricks-Tips-and-Tricks
But I want it to be
但我希望它是
index-php-title-Test/enu/test/Tips--26-Tricks/Tips-and-Tricks
Any pointers will be appreciated.
任何指针将不胜感激。
回答by Paul
You could just add your /into the regex:
您可以将您/的添加到正则表达式中：
"[^a-zA-Z0-9/]"
回答by Jonathan M
formatUrl = formatUrl.replaceAll("[^a-zA-Z0-9/]" , "-");
回答by hoipolloi
I'm wondering what you're trying to achieve. Why not just decode the URL?
我想知道你想达到什么目的。为什么不只解码 URL？
final String url = "index.php?title=Test/enu/test/Tips_%26_Tricks/Tips_and_Tricks";
final String decoded = java.net.URLDecoder.decode(url, "UTF-8");
System.out.println(decoded); // Prints index.php?title=Test/enu/test/Tips_&_Tricks/Tips_and_Tricks
