Guzzle Curl 错误没有被 try catch 语句捕获（Laravel）
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Guzzle Curl error not catche by try catch statement (Laravel)
提问by Samuel Dauzon
In a Laravel project I need to call API REST to delete remote data.
在 Laravel 项目中，我需要调用 API REST 来删除远程数据。
My problem is that my catch statement dont catch Guzzle exceptionwhen I got an error. My code is the following :
我的问题是当我遇到错误时，我的catch 语句不会捕获 Guzzle 异常。我的代码如下：
try {
$client = new \GuzzleHttp\Client();
$request = $client->delete(Config::get('REST_API').'/order-product/'.$id);
$status = $request->getStatusCode();
} catch (Exception $e) {
var_dump($e);exit();
}
The exception is catched by Laravel but not in my catchstatement. The exception throwed by Guzzle is :
该异常被 Laravel 捕获，但不在我的catch语句中。Guzzle 抛出的异常是：
GuzzleHttp\Ring\Exception\ConnectException
It raised in my line 3of script and it doesn't catched in my script. Could you give me a way to catch the Guzzle Exception?
它在我的脚本第 3 行中提出，但没有出现在我的脚本中。你能给我一种方法来捕捉 Guzzle Exception吗？
I should indicate that I already seen these posts but I not get a good response : How to resolve cURL Error (7): couldn't connect to host?and Catching cURL errors from Guzzle
我应该指出我已经看过这些帖子，但没有得到很好的回应： 如何解决 cURL 错误 (7)：无法连接到主机？并 从狂饮捕获卷曲的错误
采纳答案by Ymartin
I had a similar problem and solved it using the following thing.I have used your example and given the inline comments for you to understand.
我遇到了类似的问题并使用以下内容解决了它。我使用了您的示例并给出了内联注释以供您理解。
try {
$client = new \GuzzleHttp\Client();
$request = $client->delete(Config::get('REST_API').'/order-product/'.$id);
$status = $request->getStatusCode();
if($status == 200){
$response = $response->json();
}else{
// The server responded with some error. You can throw back your exception
// to the calling function or decide to handle it here
throw new \Exception('Failed');
}
} catch (\Guzzle\Http\Exception\ConnectException $e) {
//Catch the guzzle connection errors over here.These errors are something
// like the connection failed or some other network error
$response = json_encode((string)$e->getResponse()->getBody());
}
Hope this helps!
希望这可以帮助！
回答by Muhammad
It worked with me when I used
当我使用时它对我有用
\GuzzleHttp\Exception\ConnectException
\GuzzleHttp\Exception\ConnectException
instead of
代替
\Guzzle\Http\Exception\ConnectException
\Guzzle\Http\Exception\ConnectException
回答by Mihai Matei
Maybe that exception is not extending the Exceptionclass. You may try to catch it like:
也许那个例外没有扩展Exception类。您可以尝试像这样捕捉它：
try {
$client = new \GuzzleHttp\Client();
$request = $client->delete(Config::get('REST_API').'/order-product/'.$id);
$status = $request->getStatusCode();
} catch (\GuzzleHttp\Ring\Exception\ConnectException $e) {
var_dump($e);exit();
} catch (Exception $e) {
// ...
}
回答by Peter
You probably mean to catch \Exception(in the root namespace), either by adding the backslash in the catch statement or a use Exceptionstatement.
您可能想\Exception通过在 catch 语句或use Exception语句中添加反斜杠来捕获（在根命名空间中）。
回答by Eslam Salem Mahmoud
Just Updating the answer to the new Guzzle exception namespace
只是更新新 Guzzle 异常命名空间的答案
try {
$client = new \GuzzleHttp\Client();
$request = $client->delete(Config::get('REST_API').'/order-product/'.$id);
$status = $request->getStatusCode();
} catch (\GuzzleHttp\Exception\ConnectException $e) {
var_dump($e);exit();
}
