PHP Mailer 您必须至少提供一个电子邮件地址
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PHP Mailer You must provide at least one email address
提问by Talha Bin Shakir
require_once('phpmailer/class.phpmailer.php');
function smtpmailer($to,$from,$subject,$body) {
define('GUSER', 'xxx'); // Gmail username
define('GPWD', 'xxx'); // Gmail password
printf("list:".$to);
$recipient = array ($to);
global $error;
$mail = new PHPMailer(); // create a new object
$mail->IsSMTP(); // enable SMTP
$mail->SMTPDebug = 1; // debugging: 1 = errors and messages, 2 = messages only
$mail->SMTPAuth = true; // authentication enabled
$mail->SMTPSecure = 'ssl'; // secure transfer enabled REQUIRED for Gmail
$mail->Host = 'smtp.gmail.com';
$mail->Port = 465;
$mail->Username = GUSER;
$mail->Password = GPWD;
$mail->SetFrom($from, "Bank Negara");
$mail->Subject = $subject;
$mail->Body = $body;
foreach ($recipient as $email){
$mail->AddAddress($email);
}
if(!$mail->Send()) {
$error = 'Mail error: '.$mail->ErrorInfo;
return false;
} else {
$error = 'Message sent!';
return true;
}
}
I am passing a string which hold the email address in such format:
我正在传递一个以这种格式保存电子邮件地址的字符串：
'[email protected]','[email protected]'
When I am passing this
当我通过这个
$recipient = array ($to);
I am having error Invalid address: But When I pass the string output directly like this:
我遇到错误无效地址：但是当我像这样直接传递字符串输出时：
$recipient = array ('[email protected]','[email protected]');
It works fine. How should pass my $to String to this $recipient array.
它工作正常。如何将我的 $to String 传递给这个 $recipient 数组。
回答by Marc B
$addresses = "'[email protected]','[email protected]'";
$to = array($addresses);
is not going to magically create an array with two elements in it. What you'll get is a SINGLE element in the array, e.g
不会神奇地创建一个包含两个元素的数组。您将得到的是数组中的单个元素，例如
$to = array(
0 => "'[email protected]','[email protected]'"
);
However, doing
然而，做
$to = explode(',', $addresses);
WILL give you a two element array:
会给你一个两个元素的数组：
$to = array (
0 => "...yahoo",
1 => "...gmail"
);
