PHP DOMDocument 获取标签的属性
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PHP DOMDocument getting Attribute of Tag
提问by David Willis
Hello I have an api response in xml format with a series of items such as this:
您好，我有一个 xml 格式的 api 响应，其中包含一系列项目，例如：
<item>
<title>blah balh</title>
<pubDate>Tue, 20 Oct 2009 </pubDate>
<media:file date="today" data="example text string"/>
</item>
I want to use DOMDocument to get the attribute "data" from the tag "media:file". My attempt below doesn't work:
我想使用 DOMDocument 从标签“media:file”中获取属性“data”。我在下面的尝试不起作用：
$xmldoc = new DOMDocument();
$xmldoc->load('api response address');
foreach ($xmldoc->getElementsByTagName('item') as $feeditem) {
$nodes = $feeditem->getElementsByTagName('media:file');
$linkthumb = $nodes->item(0)->getAttribute('data');
}
What am I doing wrong? Please help.
我究竟做错了什么？请帮忙。
EDIT: I can't leave comments for some reason Mark. I get the error
编辑：由于某种原因，我不能发表评论马克。我收到错误
Call to a member function getAttribute() on a non-object
when I run my code. I have also tried
当我运行我的代码时。我也试过
$nodes = $feeditem->getElementsByTagNameNS('uri','file');
$linkthumb = $nodes->item(0)->getAttribute('data');
where uri is the uri relating to the media name space(NS) but again the same problem.
其中uri是与媒体名称空间（NS）相关的uri，但同样的问题。
Note that the media element is of the form not I think this is part of the problem, as I generally have no issue parsing for attibutes.
请注意，媒体元素的形式不是我认为这是问题的一部分，因为我通常没有解析属性的问题。
回答by Mark
The example you provided should not generate an error. I tested it and $linkthumb contained the string "example text string" as expected
您提供的示例不应产生错误。我对其进行了测试，$linkthumb 按预期包含字符串“示例文本字符串”
Ensure the medianamespace is defined in the returned XML otherwise DOMDocument will error out.
确保在返回的 XML 中定义了媒体命名空间，否则 DOMDocument 将出错。
If you are getting a specific error, please edit your post to include it
如果您遇到特定错误，请编辑您的帖子以包含它
Edit:
编辑：
Try the following code:
试试下面的代码：
$xmldoc = new DOMDocument();
$xmldoc->load('api response address');
foreach ($xmldoc->getElementsByTagName('item') as $feeditem) {
$nodes = $feeditem->getElementsByTagName('file');
$linkthumb = $nodes->item(0)->getAttribute('data');
echo $linkthumb;
}
You may also want to look at SimpleXMLand Xpathas it makes reading XML much easier than DOMDocument.
回答by Leprechaun
Alternatively,
或者，
$DOMNode -> attributes -> getNamedItem( 'MyAttribute' ) -> value;
