Java 如何将 JSONObjects 转换为 JSONArray?

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时间:2020-08-13 17:17:27  来源:igfitidea点击:

How to convert JSONObjects to JSONArray?

javaarraysjson

提问by NickUnuchek

I have a response like this:

我有这样的回应:

{
 "songs":{
          "2562862600":{"id":"2562862600""pos":1},
          "2562862620":{"id":"2562862620""pos":1},
          "2562862604":{"id":"2562862604""pos":1},
          "2573433638":{"id":"2573433638""pos":1}
         }
 }

Here is my code:

这是我的代码:

List<NameValuePair> param = new ArrayList<NameValuePair>();
JSONObject json = jParser.makeHttpRequest(url, "GET", param);

JSONObject songs= json.getJSONObject("songs");

How do I convert "songs"to a JSONArray?

如何转换"songs"为 JSONArray?

采纳答案by nikis

Something like this:

像这样的东西:

JSONObject songs= json.getJSONObject("songs");
Iterator x = songs.keys();
JSONArray jsonArray = new JSONArray();

while (x.hasNext()){
    String key = (String) x.next();
    jsonArray.put(songs.get(key));
}

回答by user3467480

Your response should be something like this to be qualified as Json Array.

你的响应应该是这样的才能被称为 Json Array。

{
  "songs":[
    {"2562862600": {"id":"2562862600", "pos":1}},  
    {"2562862620": {"id":"2562862620", "pos":1}},  
    {"2562862604": {"id":"2562862604", "pos":1}},  
    {"2573433638": {"id":"2573433638", "pos":1}}
  ]
}

You can parse your response as follows

您可以按如下方式解析您的回复

String resp = ...//String output from your source
JSONObject ob = new JSONObject(resp);  
JSONArray arr = ob.getJSONArray("songs");

for(int i=0; i<arr.length(); i++){   
  JSONObject o = arr.getJSONObject(i);  
  System.out.println(o);  
}

回答by NickUnuchek

To deserialize the response need to use HashMap:

要反序列化需要使用的响应HashMap

String resp = ...//String output from your source

Gson gson = new GsonBuilder().create();
gson.fromJson(resp,TheResponse.class);

class TheResponse{
 HashMap<String,Song> songs;
}

class Song{
  String id;
  String pos;
}

回答by plexus

Even shorter and with json-functions:

甚至更短,并带有 json 函数:

JSONObject songsObject = json.getJSONObject("songs");
JSONArray songsArray = songsObject.toJSONArray(songsObject.names());