xcode 使用 JSON Framework for Objective-C 解析嵌套的 JSON 对象

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时间:2020-09-14 19:10:37  来源:igfitidea点击:

Parsing nested JSON objects with JSON Framework for Objective-C

objective-ciphonecocoa-touchxcodejson

提问by Sheehan Alam

I have the following JSON object:

我有以下 JSON 对象:

{
"response": {
    "status": 200
},
"messages": [
    {
        "message": {
            "user": "value"
            "pass": "value",
            "url": "value"
         }
 ]
    }

}

}

I am using JSON-Framework (also tried JSON Touch) to parse through this and create a dictionary. I want to access the "message" block and pull out the "user", "pass" and "url" values.

我正在使用 JSON-Framework(也尝试过 JSON Touch)来解析它并创建一个字典。我想访问“message”块并提取“user”、“pass”和“url”值。

In Obj-C I have the following code:

在 Obj-C 中,我有以下代码:

// Create new SBJSON parser object
SBJSON *parser = [[SBJSON alloc] init];

// Prepare URL request to download statuses from Twitter
NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL URLWithString:myURL]]; 

// Perform request and get JSON back as a NSData object
NSData *response = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil];

// Get JSON as a NSString from NSData response
NSString *json_string = [[NSString alloc] initWithData:response encoding:NSUTF8StringEncoding];

//Print contents of json-string
NSArray *statuses = [parser objectWithString:json_string error:nil];
NSLog(@"Array Contents: %@", [statuses valueForKey:@"messages"]);
NSLog(@"Array Count: %d", [statuses count]);


NSDictionary *results = [json_string JSONValue];
NSArray *tweets = [[results objectForKey:@"messages"] objectForKey:@"message"];

for (NSDictionary *tweet in tweets)
{
    NSString *url = [tweet objectForKey:@"url"];
    NSLog(@"url is: %@",url);
}

I can pull out "messages" and see all of the "message" blocks, but I am unable to parse deeper and pull out the "user", "pass", and "url".

我可以拉出“消息”并查看所有“消息”块,但我无法更深入地解析并拉出“用户”、“通过”和“url”。

回答by Sheehan Alam

Solved:

解决了:

NSArray *tweets = [[results objectForKey:@"messages"] valueForKey:@"message"];

回答by Paresh Thakor

Array({

  0=>Dictionary({

      response =  Array({

        0=>Dictionary(Status = 200)

      })

    }),

  1=>Dictionary({

      messages = Array({

        0=> Dictionary({

          message = Array({

            0=>Dictionary({

              user = value,

              pass=value,

                 url=value

            })

          })

        })

      })

  })

})

So, to access dictionary for user, pass, url,

因此,要访问用户、pass、url 的字典,

nsarray *arr = jsonmainarray;


arr = [[[jsonmainarray objectAtIndex: 1] objectforkey:@"messages"] objectatindex: 0];



nsdictionary *dict = [arr objectatindex: 0];

arr = [dict objectforkey:@"message"];

dict = [arr objectatindex: 0]; // Dictionary with user, pass, url

回答by Kristian Flatheim Jensen

there is an easier way (in my opinion) to do JSON parsing :)

有一种更简单的方法(在我看来)进行 JSON 解析 :)

- (void)loadJSONData:(NSString *)u{
    NSURL *url = [NSURL URLWithString:[NSString stringWithFormat:@"http://expandurl.appspot.com/expand?url=%@", u]];
    NSData *rawJsonData = [NSData dataWithContentsOfURL:url];

    CJSONDeserializer *parser = [CJSONDeserializer new];
    NSError *error;
    NSDictionary *jsonDictionary = [parser deserializeAsDictionary:rawJsonData error:&error];

    [parser release];

    NSArray *array = [jsonDictionary objectForKey:@"urls"]; 
}

All you have to do is to use JSON touch... like Sheehan Alam mention.

你所要做的就是使用 JSON touch ......就像 Sheehan Alam 提到的那样。

Say that you got this line of JSON data:

假设你得到了这行 JSON 数据:

{ "end_url" = "http://www.youtube.com"; redirects = 0; "start_url" = "http://www.youtube.com"; status = OK; urls = ( "http://www.youtube.com" ); }

{ "end_url" = "http://www.youtube.com"; 重定向 = 0; "start_url" = "http://www.youtube.com"; 状态 = 正常;urls = ( "http://www.youtube.com" ); }

then in your JSONDictonary the data can be accessed by doing:

然后在您的 JSONDictonary 中,可以通过执行以下操作访问数据:

[jsonDictionary objectForKey:@"urls"]; //This will return an Array since URLS is a array
[jsondictionary objectForKey:@"en_url"]; //this will return an NSString since end_url is a string

Hope this help people as much as it helped me =)

希望这对人们的帮助和对我的帮助一样多 =)

sincerely yours Kristian

真诚地你的克里斯蒂安