bash 在bash脚本中查找包含所有关键字的行
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Find lines containing all keywords in bash script
提问by Siou
Essentially, I would like something that behaves similarly to:
本质上，我想要一些行为类似于：
cat file | grep -i keyword1 | grep -i keyword2 | grep -i keyword3
How can I do this with a bash script that takes a variable-length list of keyword arguments? The script should do a case-insensitive match of lines containing all keywords.
如何使用带有可变长度关键字参数列表的 bash 脚本执行此操作？该脚本应该对包含所有关键字的行进行不区分大小写的匹配。
回答by Idelic
Use this as a script
将此用作脚本
#! /bin/bash
awk -v IGNORECASE=1 -f <(
P=; for k; do [ -z "$P" ] && P="/$k/" || P="$P&&/$k/"; done
echo "$P{print}"
)
and invoke it as
并将其调用为
script.sh keyword1 keyword2 keyword3 < file
回答by TheBonsai
I don't know if this is efficient, and I think this is ugly, also there might be some utility for that, but:
我不知道这是否有效，我认为这很丑陋，也可能有一些效用，但是：
#!/bin/bash
unset keywords matchlist
keywords=("$@")
for kw in "${keywords[@]}"; do
matchlist="$matchlist /$kw/ &&"
done
matchlist="${matchlist% &&}"
# awk "$matchlist { print; }" < <(tr '[:upper:]' '[:lower:]' <file)
awk "$matchlist { print; }" file
And yes, it needs some robustness regarding special characters and stuff. It's just to show the idea.
是的，它需要一些关于特殊字符和内容的稳健性。这只是为了展示这个想法。
回答by Paused until further notice.
Give this a try:
试试这个：
shopt -s nocasematch
keywords="keyword1|keyword2|keyword3"
while read line; do [[ $line =~ $keywords ]] && echo $line; done < file
Edit:
编辑：
Here's a version that tests for all keywords being present, not just any:
这是一个测试所有存在关键字的版本，而不仅仅是任何关键字：
keywords=(keyword1 keyword2 keyword3) # or keywords=("$@")
qty=${#keywords[@]}
while read line
do
count=0
for keyword in "${keywords[@]}"
do
[[ "$line" =~ $keyword ]] && (( count++ ))
done
if (( count == qty ))
then
echo $line
fi
done < textlines
回答by ghostdog74
you can use bash 4.0++
你可以使用 bash 4.0++
shopt -s nocasematch
while read -r line
do
case "$line" in
*keyword1*) f=1;;&
*keyword2*) g=1;;&
*keyword3*)
[ "$f" -eq 1 ] && [ "$g" -eq 1 ] && echo $line;;
esac
done < "file"
shopt -u nocasematch
or gawk
或呆呆
gawk '/keyword/&&/keyword2/&&/keyword3/' file
回答by Siou
Found a way to do this with grep.
找到了一种使用 grep 执行此操作的方法。
KEYWORDS=$@
MATCH_EXPR="cat file"
for keyword in ${KEYWORDS};
do
MATCH_EXPR="${MATCH_EXPR} | grep -i ${keyword}"
done
eval ${MATCH_EXPR}
回答by Andy Lester
I'd do it in Perl.
我会用 Perl 来做。
For finding all lines that contain at least one of them:
查找至少包含其中之一的所有行：
perl -ne'print if /(keyword1|keyword2|keyword3)/i' file
For finding all lines that contain all of them:
查找包含所有这些行的所有行：
perl -ne'print if /keyword1/i && /keyword2/i && /keyword3/i' file
回答by John
Here is a script called search.shin bash that will search lines within a file or folder for all keywords specified:
这是一个search.sh在 bash 中调用的脚本，它将在文件或文件夹中搜索所有指定关键字的行：
#!/bin/bash
if [ $# -lt 2 ]; then
echo "[-] ./search.sh tools.txt python jira
file_to_search/folder_to_search keyword1 keyword2 keyword3 ..."
exit
fi
all_args="$@"
i=0
results="" # this will store the cumulative results from each keyword search
for arg in $all_args; do
if [ $i -eq 0 ]; then
# first argument is the file/folder to search
file_to_search="$arg"
i=$(($i + 1))
elif [ $i -eq 1 ]; then
# search the file/folder with first keyword (first search)
results=`grep --color=always -r -n -i "$arg" "$file_to_search"`
i=$(($i + 1))
else
# now keep searching the results from first search for other keywords
results=`echo "$results" | grep --color=always -i "$arg"`
i=$(($i + 1))
fi
done
echo "$results"
Example invocation of script above will search the 'tools.txt' file for 'python' and 'jira' keywords:
上面脚本的示例调用将在 'tools.txt' 文件中搜索 'python' 和 'jira' 关键字：
##代码##