Node.js：从请求中获取路径
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Node.js: get path from the request
提问by Nabil Djarallah
I have a service called "localhost:3000/returnStat" that should take a file path as parameter. For example '/BackupFolder/toto/tata/titi/myfile.txt'.
我有一个名为“localhost:3000/returnStat”的服务，它应该将文件路径作为参数。例如“/BackupFolder/toto/tata/titi/myfile.txt”。
How can I test this service on my browser? How can I format this request using Express for instance?
如何在我的浏览器上测试此服务？例如，如何使用 Express 格式化此请求？
exports.returnStat = function(req, res) {
var fs = require('fs');
var neededstats = [];
var p = __dirname + '/' + req.params.filepath;
fs.stat(p, function(err, stats) {
if (err) {
throw err;
}
neededstats.push(stats.mtime);
neededstats.push(stats.size);
res.send(neededstats);
});
};
回答by Gaurav
var http = require('http');
var url = require('url');
var fs = require('fs');
var neededstats = [];
http.createServer(function(req, res) {
if (req.url == '/index.html' || req.url == '/') {
fs.readFile('./index.html', function(err, data) {
res.end(data);
});
} else {
var p = __dirname + '/' + req.params.filepath;
fs.stat(p, function(err, stats) {
if (err) {
throw err;
}
neededstats.push(stats.mtime);
neededstats.push(stats.size);
res.send(neededstats);
});
}
}).listen(8080, '0.0.0.0');
console.log('Server running.');
I have not tested your code but other things works
我还没有测试过你的代码，但其他事情有效
If you want to get the path info from request url
如果您想从请求 url 中获取路径信息
var url_parts = url.parse(req.url);
console.log(url_parts);
console.log(url_parts.pathname);
1.If you are getting the URL parameters still not able to read the file just correct your file path in my example. If you place index.html in same directory as server code it would work...
1.如果您获得的 URL 参数仍然无法读取文件，请在我的示例中更正您的文件路径。如果你将 index.html 放在与服务器代码相同的目录中，它会起作用......
2.if you have big folder structure that you want to host using node then I would advise you to use some framework like expressjs
2.如果您想使用 node 托管大文件夹结构，那么我建议您使用诸如 expressjs 之类的框架
If you want raw solution to file path
如果您想要文件路径的原始解决方案
var http = require("http");
var url = require("url");
function start() {
function onRequest(request, response) {
var pathname = url.parse(request.url).pathname;
console.log("Request for " + pathname + " received.");
response.writeHead(200, {"Content-Type": "text/plain"});
response.write("Hello World");
response.end();
}
http.createServer(onRequest).listen(8888);
console.log("Server has started.");
}
exports.start = start;
source : http://www.nodebeginner.org/
回答by Sagiv Ofek
simply call req.url. that should do the work. you'll get something like /something?bla=foo
只需调用req.url. 那应该做的工作。你会得到类似的东西/something?bla=foo
回答by kumbhani bhavesh
You can use this in app.jsfile .
您可以在app.js文件中使用它。
var apiurl = express.Router();
apiurl.use(function(req, res, next) {
var fullUrl = req.protocol + '://' + req.get('host') + req.originalUrl;
next();
});
app.use('/', apiurl);
回答by Xin
req.protocol + '://' + req.get('host') + req.originalUrl
or
或者
req.protocol + '://' + req.headers.host + req.originalUrl// I like this one as it survives from proxy server, getting the original host name
req.protocol + '://' + req.headers.host + req.originalUrl// 我喜欢这个，因为它从代理服务器中幸存下来，获取原始主机名
回答by Ideabile
Based on @epegzz suggestion for the regex.
基于@epegzz 对正则表达式的建议。
( url ) => {
return url.match('^[^?]*')[0].split('/').slice(1)
}
returns an array with paths.
返回一个带有路径的数组。
回答by loretoparisi
Combining solutions above when using express request:
使用快递请求时结合上述解决方案：
let url=url.parse(req.originalUrl);
let page = url.parse(uri).path?url.parse(uri).path.match('^[^?]*')[0].split('/').slice(1)[0] : '';
this will handle all cases like
这将处理所有情况，例如
localhost/page
localhost:3000/page/
/page?item_id=1
localhost:3000/
localhost/
etc. Some examples:
等一些例子：
> urls
[ 'http://localhost/page',
'http://localhost:3000/page/',
'http://localhost/page?item_id=1',
'http://localhost/',
'http://localhost:3000/',
'http://localhost/',
'http://localhost:3000/page#item_id=2',
'http://localhost:3000/page?item_id=2#3',
'http://localhost',
'http://localhost:3000' ]
> urls.map(uri => url.parse(uri).path?url.parse(uri).path.match('^[^?]*')[0].split('/').slice(1)[0] : '' )
[ 'page', 'page', 'page', '', '', '', 'page', 'page', '', '' ]
