string 在shell脚本中获取子字符串
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get sub string in shell script
提问by derrdji
if I have a string like some/unknown/amount/of/sub/folder/file.txthow can I get only the the file.txtsub string, remove the front part, while the length is unknown.
如果我有一个字符串，比如some/unknown/amount/of/sub/folder/file.txt如何只获取file.txt子字符串，请删除前面的部分，而长度未知。
thank you
谢谢你
EDIT: file name could be any length, and sub folders could be any levels.
编辑：文件名可以是任意长度，子文件夹可以是任意级别。
采纳答案by Matthew Flaschen
Use basenamecommand:
使用basename命令：
orig_path="some/unknown/amount/of/sub/folder/file.txt"
last_comp=$(basename $orig_path)
echo $last_comp
回答by Stefano Borini
$ basename "some/unknown/amount/of/sub/folder/file.txt"
file.txt
To generically extract a substring, you can use this syntax
要一般提取子字符串，您可以使用此语法
$ hello="abcdef"
$ echo ${hello:1:3}
bcd
回答by William Pursell
While I agree that the correct answer is to invoke basename, in bash you can also use ## to delete the longest occurrence of a string from the start of a variable.
虽然我同意正确的答案是调用 basename，但在 bash 中，您也可以使用 ## 从变量的开头删除最长出现的字符串。
bash-3.2$ t=/this/is/a/path
bash-3.2$ echo ${t##*/}
path
回答by Oleksandr Tymoshenko
basename some/unknown/amount/of/sub/folder/file.txt
basename some/unknown/amount/of/sub/folder/file.txt
