javascript 如何将 D3 树布局的方向更改 90 度
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How to change orientation of a D3 tree layout by 90 degrees
提问by lion
I just started getting involved in web visualizations, so I'm totally novice. My goal is to display a family tree where a root node would have both multiple parents and children. While looking for a solution I found this example: http://bl.ocks.org/jdarling/2503502It's great because it seems to have the feature I need. However, I would like to alter the orientation (top-to-bottom). I tried to do so using this example: http://bl.ocks.org/mbostock/3184089but failed.
我刚刚开始参与网络可视化，所以我完全是新手。我的目标是显示一个家谱，其中根节点将有多个父节点和子节点。在寻找解决方案时，我发现了这个示例：http: //bl.ocks.org/jdarling/2503502这很棒，因为它似乎具有我需要的功能。但是，我想改变方向（从上到下）。我尝试使用以下示例这样做：http: //bl.ocks.org/mbostock/3184089但失败了。
My code:
我的代码：
var tree = d3.layout.tree()
.size([height, width]);
var diagonal = d3.svg.diagonal()
.projection(function(d) {
return [d.x, d.y];
});
var elbow = function (d, i){
var source = calcTop(d.source);
var target = calcTop(d.target);
var hx = (target.x-source.x)/2;
if(d.isRight)
hx = -hx;
return "M" + source.x + "," + source.y
+ "H" + (source.x+hx)
+ "V" + target.y + "H" + target.x;
};
var connector = elbow;
var calcTop = function(d){
var top = d.x;
if(!d.isRight){
top = d.x-halfHeight;
top = halfHeight - top;
}
return {x : top, y : d.y};
};
var vis = d3.select("#chart")
.append("svg")
.attr("height", height + margin.top + margin.bottom)
.attr("width", width + margin.right + margin.left)
.append("g")
.attr("transform", "translate(" + margin.left + "," + margin.top + ")");
d3.json("tree.json", function(json) {
root = json;
root.x0 = height / 2;
root.y0 = width / 2;
var t1 = d3.layout.tree()
.size([halfHeight, width])
.children(function(d){
return d.winners;
});
var t2 = d3.layout.tree()
.size([halfHeight, width])
.children(function(d){
return d.challengers;
});
t1.nodes(root);
t2.nodes(root);
var rebuildChildren = function(node){
node.children = getChildren(node);
if(node.children)
node.children.forEach(rebuildChildren);
}
rebuildChildren(root);
root.isRight = false;
update(root);
});
var toArray = function(item, arr){
arr = arr || [];
var i = 0, l = item.children?item.children.length:0;
arr.push(item);
for(; i < l; i++){
toArray(item.children[i], arr);
}
return arr;
};
function update(source) {
// Compute the new tree layout.
var nodes = toArray(source);
// Normalize for fixed-depth.
nodes.forEach(function(d) { d.x = d.depth * 180 + halfHeight; });
// Update the nodes…
var node = vis.selectAll("g.node")
.data(nodes, function(d) { return d.id || (d.id = ++i); });
// Enter any new nodes at the parent's previous position.
var nodeEnter = node.enter().append("g")
.attr("class", "node")
.attr("transform", function(d) {
return "translate(" + source.x0 + "," + source.y0 + ")";
})
.on("click", click);
nodeEnter.append("circle")
.attr("r", 1e-6)
.style("fill", function(d) {
return d._children ? "lightsteelblue" : "#fff";
});
nodeEnter.append("text")
.attr("dy", function(d) { return d.isRight?14:-8;})
.attr("text-anchor", "middle")
.text(function(d) { return d.name; })
.style("fill-opacity", 1e-6);
// Transition nodes to their new position.
var nodeUpdate = node.transition()
.duration(duration)
.attr("transform", function(d) {
p = calcTop(d);
return "translate(" + p.x + "," + p.y + ")";
});
nodeUpdate.select("circle")
.attr("r", 4.5)
.style("fill", function(d) {
return d._children ? "lightsteelblue" : "#fff";
});
nodeUpdate.select("text")
.style("fill-opacity", 1);
// Transition exiting nodes to the parent's new position.
var nodeExit = node.exit().transition()
.duration(duration)
.attr("transform", function(d) {
p = calcTop(d.parent||source);
return "translate(" + p.x + "," + p.y + ")";
})
.remove();
nodeExit.select("circle")
.attr("r", 1e-6);
nodeExit.select("text")
.style("fill-opacity", 1e-6);
// Update the links...
var link = vis.selectAll("path.link")
.data(tree.links(nodes), function(d) { return d.target.id; });
// Enter any new links at the parent's previous position.
link.enter().insert("path", "g")
.attr("class", "link")
.attr("d", function(d) {
var o = {x: source.x0, y: source.y0};
return connector({source: o, target: o});
});
// Transition links to their new position.
link.transition()
.duration(duration)
.attr("d", connector);
// Transition exiting nodes to the parent's new position.
link.exit()
.transition()
.duration(duration)
.attr("d", function(d) {
var o = calcTop(d.source||source);
if(d.source.isRight)
o.x -= halfHeight - (d.target.x - d.source.x);
else
o.x += halfHeight - (d.target.x - d.source.x);
return connector({source: o, target: o});
})
.remove();
// Stash the old positions for transition.
nodes.forEach(function(d) {
var p = calcTop(d);
d.x0 = p.x;
d.y0 = p.y;
});
// Toggle children on click.
function click(d) {
if (d.children) {
d._children = d.children;
d.children = null;
} else {
d.children = d._children;
d._children = null;
}
update(source);
} }
} }
Would really appreciate the help!
非常感谢您的帮助！
回答by lion
The example you're looking at is actually already flipped - this might be causing you some confusion. Trees in D3 are naturally top-down trees, and the code does a lot of x-y flipping to make the tree sideways.
您正在查看的示例实际上已经翻转了 - 这可能会引起您的一些困惑。D3 中的树自然是自顶向下的树，代码做了很多 xy 翻转，使树侧身。
Changing
改变
var nodeUpdate = node.transition()
.duration(duration)
.attr("transform", function(d) { p = calcLeft(d); return "translate(" + p.y + "," + p.x + ")"; })
;
to
到
var nodeUpdate = node.transition()
.duration(duration)
.attr("transform", function(d) { p = calcLeft(d); return "translate(" + p.x + "," + p.y + ")"; })
;
will get the nodes displaying in the right position. Doing a similar change with any instance of swapped x-y coordinates inside update() fixes most of the positioning issues. One last thing is the elbow function/variable/whatever you want to call it, where
将使节点显示在正确的位置。对 update() 内的任何交换 xy 坐标实例进行类似更改可修复大部分定位问题。最后一件事是肘部函数/变量/无论你想怎么称呼它，在哪里
return "M" + source.y + "," + source.x
+ "H" + (source.y+hy)
+ "V" + target.x + "H" + target.y;
should be changed to
应该改为
return "M" + source.x + "," + source.y
+ "V" + (source.y+hy)
+ "H" + target.x + "V" + target.y;
This changes the connector shape from horizontal vertical horizontal to vertical horizontal vertical. Note that this is a raw SVG line, not d3 at all. The changes I made (plus swapping width and height, and changing the AJAX JSON request to hardcoding the data - AJAX is hard to get working in fiddle) are all at http://jsfiddle.net/Zj3th/2/.
这会将连接器形状从水平垂直水平更改为垂直水平垂直。请注意，这是一个原始的 SVG 行，根本不是 d3。我所做的更改（加上交换宽度和高度，以及更改 AJAX JSON 请求以对数据进行硬编码 - AJAX 很难在小提琴中工作）都在http://jsfiddle.net/Zj3th/2/。
If you have no experience with d3 and SVG, I would definitely take a look and fully understand a simple example like http://blog.pixelingene.com/2011/07/building-a-tree-diagram-in-d3-js/before you go further in modifying the code.
如果您没有使用 d3 和 SVG 的经验，我肯定会看一下并完全理解一个简单的例子，比如http://blog.pixelingene.com/2011/07/building-a-tree-diagram-in-d3-js /在进一步修改代码之前。
回答by VividD
回答by Aravind Cheekkallur
its very easy to make rotation in d3 collapsible tree TOP-DOWN..
step 1: specify top,bottom,left,right part of our drawing pan and also the width and
height.
Step 2: Make the orientation as top to bottom
step 3: Reading the json and make the orientation
step 4: Appending the link and circle to the body
<script>
var jdata='${data}'
var margin = {top: 20, right: 120, bottom: 20, left: 120},
width = 980 - margin.left - margin.right,
height = 500 - margin.top - margin.bottom;
var orientations = {
"top-to-bottom": {
size: [width, height],
x: function(d) { return d.x; },
y: function(d) { return d.y; }
}
};
var svg = d3.select("body").selectAll("svg")
.data(d3.entries(orientations))
.enter().append("svg")
.attr("width", width + margin.left + margin.right)
.attr("height", height + margin.top + margin.bottom)
.append("g")
.attr("transform", "translate(" + margin.left + "," + margin.top + ")");
d3.json("resources/grap.json", function(json) {
root = JSON.parse(jdata);
svg.each(function(orientation) {
var svg = d3.select(this),
o = orientation.value;
// Compute the layout.
var tree = d3.layout.tree().size(o.size),
nodes = tree.nodes(root),
links = tree.links(nodes);
// Create the link lines.
svg.selectAll(".link")
.data(links)
.enter().append("path")
.attr("class", "link")
.attr("d", d3.svg.diagonal().projection(function(d) { return [o.x(d), o.y(d)]; }));
// Create the node circles.
svg.selectAll(".node")
.data(nodes)
.enter().append("circle")
.attr("r",1.5)
.attr("x", o.x)
.attr("y", o.y)
});
});
</script>
