python 检查python中目录的权限
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check permissions of directories in python
提问by vartec
i want a python program that given a directory, it will return all directories within that directory that have 775 (rwxrwxr-x) permissions
我想要一个给定目录的 python 程序，它将返回该目录中具有 775 ( rwxrwxr-x) 权限的所有目录
thanks!
谢谢！
回答by lt_kije
Neither answer recurses, though it's not entirely clear that that's what the OP wants. Here's a recursive approach (untested, but you get the idea):
这两个答案都不会重复，尽管并不完全清楚这就是 OP 想要的。这是一种递归方法（未经测试，但您明白了）：
import os
import stat
import sys
MODE = "775"
def mode_matches(mode, file):
"""Return True if 'file' matches 'mode'.
'mode' should be an integer representing an octal mode (eg
int("755", 8) -> 493).
"""
# Extract the permissions bits from the file's (or
# directory's) stat info.
filemode = stat.S_IMODE(os.stat(file).st_mode)
return filemode == mode
try:
top = sys.argv[1]
except IndexError:
top = '.'
try:
mode = int(sys.argv[2], 8)
except IndexError:
mode = MODE
# Convert mode to octal.
mode = int(mode, 8)
for dirpath, dirnames, filenames in os.walk(top):
dirs = [os.path.join(dirpath, x) for x in dirnames]
for dirname in dirs:
if mode_matches(mode, dirname):
print dirname
Something similar is described in the stdlib documentation for stat.
stat的 stdlib 文档中描述了类似的内容 。
回答by Brian
回答by vartec
Compact generator based on Brian's answer:
基于布莱恩的回答的紧凑型发电机：
import os
(fpath for fpath
in (os.path.join(dirname,fname) for fname in os.listdir(dirname))
if (os.path.isdir(fpath) and (os.stat(fpath).st_mode & 0777) == 0775))
回答by lithorus
Does it have to be python?
它必须是python吗？
You can also use find to do that :
您也可以使用 find 来做到这一点：
"find . -perm 775"
“找到 .-perm 775”
