Java 在 spring 框架中使用在类路径资源 [application-context.xml] 中定义的名称创建 bean 时出错
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Error creating bean with name defined in class path resource [application-context.xml] in spring framework
提问by M06H
<bean id="MyDataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="com.mysql.jdbc.Driver"/>
<property name="url" value="${url}"/>
<property name="username" value="${username}"/>
<property name="password" value="${password}"/>
</bean>
<bean id="template" class="org.springframework.jdbc.core.JdbcTemplate">
<constructor-arg value="MyDataSource"/>
</bean>
Error creating bean with name 'template' defined in class path resource [application-context.xml]: Could not resolve matching constructor (hint: specify index/type/name arguments for simple parameters to avoid type ambiguities)
使用在类路径资源 [application-context.xml] 中定义的名称“模板”创建 bean 时出错：无法解析匹配的构造函数（提示：为简单参数指定索引/类型/名称参数以避免类型歧义）
I am not sure what I am doing wrong here to get above error? Have all of it defined in properties file correctly with correct variable name. what are the things to check for ?
我不确定我在这里做错了什么来获得上述错误？使用正确的变量名称在属性文件中正确定义所有这些。需要检查什么？
采纳答案by Jigar Joshi
change
改变
<bean id="template" class="org.springframework.jdbc.core.JdbcTemplate">
<constructor-arg value="MyDataSource"/>
</bean>
to
到
<bean id="template" class="org.springframework.jdbc.core.JdbcTemplate">
<constructor-arg ref="MyDataSource"/>
</bean>
because you don't want to inject Stringvalue you want to inject referred bean
因为你不想注入String你想要注入引用 bean 的值
