Java Play Framework 2.2 : 获取请求页面的 URL
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Play Framework 2.2 : Get URL of the requesting page
提问by Incpetor
PLAY FRAMEWORK JAVA:
玩框架Java：
I am trying to get the name of the URL that requested the controller function. For example , I have a routes as
我正在尝试获取请求控制器功能的 URL 的名称。例如，我有一个路线
GET /mypage controllers.Mypage.myfunction()
GET /mypage controllers.Mypage.myfunction()
and I have another page that requests the same controller
我有另一个页面请求相同的控制器
GET /anotherpage controllers.Mypage.myfunction()
GET /anotherpage controllers.Mypage.myfunction()
is there a way to find in controllers if the request is from /mypageor from /anotherpage?
有没有办法在控制器中找到请求是来自/mypage还是来自/anotherpage？
Thanks
谢谢
采纳答案by Michael Zajac
Say you visit example.com:9000/login?param=test, then within your controller function:
假设您访问example.com:9000/login?param=test，然后在您的控制器功能中：
public static Result login() {
// set to "/login" -- The URI path without query parameters.
String path = request().path();
// set to "/login?param=test" -- The full URI.
String uri = request().uri();
// set to "example.com:9000" -- The host name from the request, with port (if specified by the client).
String host = request().host();
...
}
回答by Govind Singh
you didn't mention language
你没有提到语言
In Scala you can get path in controller by
在 Scala 中，您可以通过以下方式获取控制器中的路径
val path= request.path
or
或者
val path=request.uri
i have tried this in play framework 2.2*
我已经在 play framework 2.2* 中尝试过这个
In Java
在 Java 中
String path= request.path();
or
或者
String path=request.url();
according to this link http://www.playframework.com/documentation/1.0.1/api/play/mvc/Http.Request.html
根据这个链接 http://www.playframework.com/documentation/1.0.1/api/play/mvc/Http.Request.html
