Java中的数字到单词的转换
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Number to Word Conversion in Java
提问by Jeremiah Pleas Eugene Johnson
I have this homework assignment for this class I'm retaking, the problem I'm running into is that I'm over-thinking the solution. I have to create a program that converts a four digit number to words.
我要重修这门课的家庭作业,我遇到的问题是我想太多了。我必须创建一个将四位数字转换为单词的程序。
(Example: 1134 becomes "One One Three Four")
(例如:1134变成“一一三四”)
I have a basic code, but it's bulky and ugly. I'm also only allowed to use basic if and switch statements, we have to use a switch statement as well.
我有一个基本的代码,但它又大又丑。我也只允许使用基本的 if 和 switch 语句,我们也必须使用 switch 语句。
Am I over thinking this? I can't figure out how to make this code shorter and I only want to use one switch statement without a while loop. Is it even possible or is this as short as it gets.
我是不是想多了?我不知道如何缩短这段代码,我只想使用一个没有 while 循环的 switch 语句。它甚至可能还是尽可能短。
Here's my code.
这是我的代码。
import java.util.Scanner;
public class NumberToWords {
public static void main(String[] args) {
//Set up scanner.
Scanner kb = new Scanner(System.in);
//Ask for a 4 digit integer.
System.out.println("Enter a 4 digit number.");
//Store 4 digit number into a variable
int number = kb.nextInt();
//Seperate number into digits.
int digit4 = number%10;
number = number/10;
int digit3 = number%10;
number = number/10;
int digit2 = number%10;
number = number/10;
int digit1 = number%10;
number = number/10;
//Set up a switch statement to read through the number.
switch (digit1)
{
case 1: System.out.print("One ");break;
case 2: System.out.print("Two "); break;
case 3: System.out.print("Three "); break;
case 4: System.out.print("Four "); break;
case 5: System.out.print("Five "); break;
case 6: System.out.print("Six "); break;
case 7: System.out.print("Seven "); break;
case 8: System.out.print("Eight "); break;
case 9: System.out.print("Nine "); break;
case 0: System.out.print("Zero "); break;
default: System.out.print(""); break;
}
switch (digit2)
{
case 1: System.out.print("One ");break;
case 2: System.out.print("Two "); break;
case 3: System.out.print("Three "); break;
case 4: System.out.print("Four "); break;
case 5: System.out.print("Five "); break;
case 6: System.out.print("Six "); break;
case 7: System.out.print("Seven "); break;
case 8: System.out.print("Eight "); break;
case 9: System.out.print("Nine "); break;
case 0: System.out.print("Zero "); break;
default: System.out.print(""); break;
}
switch (digit3)
{
case 1: System.out.print("One ");break;
case 2: System.out.print("Two "); break;
case 3: System.out.print("Three "); break;
case 4: System.out.print("Four "); break;
case 5: System.out.print("Five "); break;
case 6: System.out.print("Six "); break;
case 7: System.out.print("Seven "); break;
case 8: System.out.print("Eight "); break;
case 9: System.out.print("Nine "); break;
case 0: System.out.print("Zero "); break;
default: System.out.print(""); break;
}
switch (digit4)
{
case 1: System.out.print("One ");break;
case 2: System.out.print("Two "); break;
case 3: System.out.print("Three "); break;
case 4: System.out.print("Four "); break;
case 5: System.out.print("Five "); break;
case 6: System.out.print("Six "); break;
case 7: System.out.print("Seven "); break;
case 8: System.out.print("Eight "); break;
case 9: System.out.print("Nine "); break;
case 0: System.out.print("Zero "); break;
default: System.out.print(""); break;
}
}
}
回答by Xogle
Yeah, you can simply do that operation in a for loop, executed 4 times. The division and mod is consistent at 10. Something like
是的,您可以简单地在 for 循环中执行该操作,执行 4 次。除法和 mod 一致为 10。类似的东西
For i = 0; i < 4; i++
Number/10%10
Condition to check number
Save number in array or print
回答by Elliott Frisch
First, write a method to convert a single digit to a word. Something like,
首先,编写一个将单个数字转换为单词的方法。就像是,
private static String digitToWord(char ch) {
switch(ch) {
case '0': return "Zero";
case '1': return "One";
case '2': return "Two";
case '3': return "Three";
case '4': return "Four";
case '5': return "Five";
case '6': return "Six";
case '7': return "Seven";
case '8': return "Eight";
case '9': return "Nine";
}
return "Unknown (" + ch + ")";
}
Then you can get the String
value of your int
. And get the four characters from that String
. Something like,
然后你可以得到String
你的int
. 并从中获取四个字符String
。就像是,
int number = kb.nextInt();
String str = String.format("%04d", number);
StringBuilder sb = new StringBuilder();
sb.append(digitToWord(str.charAt(0)).append(' ');
sb.append(digitToWord(str.charAt(1)).append(' ');
sb.append(digitToWord(str.charAt(2)).append(' ');
sb.append(digitToWord(str.charAt(3));
System.out.println(sb.toString());
Or,
或者,
String str = String.format("%04d", kb.nextInt());
System.out.printf("%s %s %s %s%n", digitToWord(str.charAt(0)),
digitToWord(str.charAt(1)), digitToWord(str.charAt(2)),
digitToWord(str.charAt(3)));
回答by nmore
Copy pasting code and names with numbers should be a red flag to use a loop (or something more is worng).
复制粘贴代码和带有数字的名称应该是使用循环的危险信号(或更多的东西)。
private static final String[] DIGIT_NAMES = new String[] {"Zero ", "One ", "Two ",
"Three ", "Four ", "Five ", "Six ", "Seven ", "Eight ", "Nine "};
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
int number = 0;
do {
// ask for a 4 digit integer
System.out.println("Enter a 4 digit number: ");
try {
number = input.nextInt();
} catch (InputMismatchException ignore) {
System.out.println("Recieved non integer input");
input.next(); // clear bad input
}
} while (number < 1000 || number > 9999);
String result = "";
while (number != 0) {
result = DIGIT_NAMES[number % 10] + result;
number = number / 10;
}
System.out.println(result);
input.close();
}
回答by Shuchi Jain
this might help
这可能有帮助
public class NumbersInWords {
public static void main(String[] args) {
String number = "153";
int numLength = number.length();
System.out.println(numLength);
String numberToWord = "";
for (int j = 0; j < numLength; j++) {
switch (number.charAt(j)) {
case '1': {
numberToWord = numberToWord + "one";
break;
}
case '2': {
numberToWord = numberToWord + "two";
break;
}
case '3': {
numberToWord = numberToWord + "three";
break;
}
case '4': {
numberToWord = numberToWord + "four";
break;
}
case '5': {
numberToWord = numberToWord + "five";
break;
}
case '6': {
numberToWord = numberToWord + "six";
break;
}
case '7': {
numberToWord = numberToWord + "seven";
break;
}
case '8': {
numberToWord = numberToWord + "eight";
break;
}
case '9': {
numberToWord = numberToWord + "nine";
break;
}
default: {
numberToWord = numberToWord + "zero";
}
}
}
System.out.println(numberToWord);
}
}