javascript 检查 textarea 是否为空

声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow 原文地址: http://stackoverflow.com/questions/14455728/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me): StackOverFlow

提示:将鼠标放在中文语句上可以显示对应的英文。显示中英文
时间:2020-10-26 21:40:19  来源:igfitidea点击:

check whether a textarea is empty

javascripthtml

提问by suhas

Can anyone please tell me what the problem is with this code:

谁能告诉我这段代码有什么问题:

function c(id)
{
    var empty = document.getElementById(id);
    if(empty.length<1)
    {
        window.alert ("This field cant be left empty");
        return true;
    }
    else
    {
        return false;
    }

}

This is my html code:

这是我的 html 代码:

<textarea rows="3" cols="80" id="ta1" onChange="c('ta1');"></textarea>

回答by Kevin Bowersox

The value property of the textarea should be checked to determine if it is empty.

应检查 textarea 的 value 属性以确定它是否为空。

   var content = document.getElementById(id).value;

   if(content.length<1)
   {
        window.alert ("This field cant be left empty");
        return true;
   }
   else
   {
        return false;
   }

Working Example: http://jsfiddle.net/35DFR/2/

工作示例:http: //jsfiddle.net/35DFR/2/

回答by Gjordis

if (YOURFORM.YOURTEXTFIELDVARIABLENAME.value == "")

{
     return True

}

回答by skub

Try this:

试试这个:

function c(id)
{
    if(document.getElementById(id).value == '')
    {
        window.alert ("This field cant be left empty");
        return true;
    }
    else
    {
        return false;
    }

}

If you want to go a bit further, you might want to trim the value first though.

如果您想更进一步,您可能需要先修剪该值。

Update:

更新:

From the comments, try changing the 'onchange' to 'onkeyup':

从评论中,尝试将“ onchange”更改为“ onkeyup”:

<textarea rows="3" cols="80" id="ta1" onkeyup="c('ta1');"></textarea>

回答by wildpea

function c(id) {
    var empty =document.getElementById(id);
    if(!empty.value){
        window.alert("This field cant be left empty");
        return true;
    }else{
        return false;
    }
}

try this

试试这个