C语言 字符数组不可分配
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char array not assignable
提问by Luxuspunch
Okay, so I want to save a word in a char array but it gives me a error
好的，所以我想在字符数组中保存一个单词，但它给了我一个错误
Here's my code
这是我的代码
#include <stdio.h>
#include <time.h>
#include <stdlib.h>
#include <string.h>
int main(void)
{
char yesno[30] = "n"; //yes/no answer
char class[30] = "undefined";//choosen class
int classchoosen = 0;
/* initialize random seed: */
srand ( time(NULL) );
printf("Welcome, which class do you wanna play with? \n");
printf("Type W for Warrior, M for Mage or R for Ranger. Then press Enter\n");
while(classchoosen == 0)
{
scanf("%s", class);
if(strcmp(class, "W") == 0)
{
classchoosen = 1;
class = "Warrior";
}
if(strcmp(class, "M") == 0)
{
classchoosen = 1;
class = "Mage";
}
if(strcmp(class, "R") == 0)
{
classchoosen = 1;
class = "Ranger";
}
if(classchoosen == 0)
{
class = "undefined";
}
printf("So you wanna play as a %s? Enter y/n", class);
classchoosen = 0; //For testing, remove later
}
while(1)
{
/* Irrelevant stuff */
}
}
And it gives me following errors:
它给了我以下错误：
damagecalc.c:44:13: error: expected identifier
class -> "warrior";
^
damagecalc.c:49:10: error: array type 'char [30]' is not assignable
class = "mage";
~~~~~ ^
damagecalc.c:54:10: error: array type 'char [30]' is not assignable
class = "ranger";
~~~~~ ^
damagecalc.c:58:10: error: array type 'char [30]' is not assignable
class = "warlock";
~~~~~ ^
4 errors generated.
I know I could just print out the class name just after the string comparison, but this thing is really bugging me and I want to know why it doesn't work.
我知道我可以在字符串比较之后打印出类名，但是这件事真的让我烦恼，我想知道为什么它不起作用。
PS: Please forgive me for any obvious mistakes I may do, I just got into PC programming recently after having worked on uC's for a couple of years.
PS：请原谅我可能犯的任何明显错误，我在 uC 上工作了几年后最近才进入 PC 编程。
回答by Iharob Al Asimi
Yes chararrays are not assignable just as all arrays aren't. You should use strcpyfor example
是的，char数组不可分配，就像所有数组都不可分配一样。你应该使用strcpy例如
strcpy(class, "Warrior");
and so on.
等等。
Also, you don't need to declare char class[30];the longest string I see in your code is "undefined"so
此外，您不需要声明char class[30];中最长的字符串我看到你的代码是"undefined"这样
char class[10];
should be ok, 9characters of "undefined"+ 1 null terminating byte '\0'.
应该没问题9，"undefined"+ 1 个空终止字节的字符'\0'。
And you should prevent buffer overflow with scanfthis way
你应该用scanf这种方式防止缓冲区溢出
scanf("%1s", class);
since you only want to read 1character, also the comparison should be simpler just
由于您只想读取1字符，因此比较应该更简单
if (class[0] == 'M')
strcpy(class, "Mage");
or even thsi would be more readable
甚至thsi会更具可读性
classchosen = 1;
switch (class[0])
{
case 'M':
strcpy(class, "Mage");
break;
case 'R':
strcpy(class, "Ranger");
break;
case 'W':
strcpy(class, "Warrior");
break;
default:
classchosen = 0;
}
and finally check that scanfactually succeeded, it returns the number of arguments matched so in your case a check would be like
最后检查是否scanf实际成功，它返回匹配的参数数量，因此在您的情况下，检查将类似于
if (scanf("%1s", class) == 1) ...
回答by Anurag Bhakuni
see this is not only for character array , this implies for all type of arrays but the question aries why?,when we can assign other variable why not array the thing is:- suppose we have:
看到这不仅适用于字符数组，这意味着适用于所有类型的数组，但问题是为什么？，当我们可以分配其他变量时，为什么不是数组，事情是：-假设我们有：
int a[size];
a = {2,3,4,5,6};
because here the name of an array mean address of the first location of an array
因为这里的数组名是指数组第一个位置的地址
printf("%p",a); // let suppose the output is 0x7fff5fbff7f0
We are saying by that
我们是这么说的
0x7fff5fbff7f0 = something; which is not correct yes we can do a[0] = something , now it saying assign the value of array at 0th location.
0x7fff5fbff7f0 = 某物；这是不正确的，我们可以做 a[0] = something ，现在它说在第 0 个位置分配数组的值。
回答by Gopi
class = "Ranger";
should be
应该
strcpy(class,"Ranger");
Fix the same in all the places. char arrays are not assignable
在所有地方修复相同。字符数组不可分配
回答by Meninx - メネンックス
switch class = "Warrior";to strcpy(class, "warrior");
切换class = "Warrior";到strcpy(class, "warrior");
switch class = "Mage";to strcpy(class, "Mage");
切换class = "Mage";到strcpy(class, "Mage");
switch class = "Ranger";to strcpy(class, "Ranger");
切换class = "Ranger";到strcpy(class, "Ranger");
switch class = "undefined";to strcpy(class, "undefined");
切换class = "undefined";到strcpy(class, "undefined");
and it should work !
它应该工作！
