Javascript PHP 使用包含在页面上设置活动链接
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PHP set active link on page using includes
提问by nowayyy
So I have searched SO for an hour trying to find the answer, and also tried various methods, including this
所以我搜索了一个小时试图找到答案，并尝试了各种方法，包括这个
I am trying to include my pages, along with the navigation. But on the correct page, I need the list-item to have a class of active. The navigation is in header.php and currently looks like this:
我正在尝试包含我的页面以及导航。但是在正确的页面上，我需要列表项具有active. 导航在 header.php 中，目前看起来像这样：
<nav>
<ul>
<li class="active"> <a href="/">Home</a> </li>
<li> <a href="#">Apps</a> </li>
<li> <a href="#">Forums</a> </li>
</ul>
</nav>
First, I have no idea if JS(jQuery) would be better, or if PHP was to be better. Both wouldn't matter if it works.
首先，我不知道 JS(jQuery) 是否会更好，或者 PHP 是否会更好。如果它有效，两者都无关紧要。
Also I am a bit new with PHP and trying to learn.
此外，我对 PHP 有点陌生，正在努力学习。
What would be the easiest (hopefully) method to use? So I don't have to change a lot of code just to give a nav class="active"
什么是最简单（希望）使用的方法？所以我不必为了提供导航而更改很多代码class="active"
回答by Naftali aka Neal
Asumming you have a $pagevariable (which contains the name of the page you are currently on):
假设您有一个$page变量（其中包含您当前所在页面的名称）：
<nav>
<ul>
<li class="<?php echo ($page == "home" ? "active" : "")?>"> <a href="/">Home</a> </li>
<li class="<?php echo ($page == "apps" ? "active" : "")?>"> <a href="#">Apps</a> </li>
<li class="<?php echo ($page == "forums" ? "active" : "")?>"> <a href="#">Forums</a> </li>
</ul>
</nav>
回答by Niklas Andersson
Here is a simple way where you do not need to add any other variable
这是一种无需添加任何其他变量的简单方法
<li class="<?php echo ($_SERVER['PHP_SELF'] == "/index.php" ? "active" : "");?>">
<a href="index.php">Start</a>
</li>
<li class="<?php echo ($_SERVER['PHP_SELF'] == "/about.php" ? "active" : "");?>">
<a href="about.php">About</a>
</li>
<li class="<?php echo ($_SERVER['PHP_SELF'] == "/practices.php" ? "active" : "");?>">
<a href="practices.php">Practices</a>
</li>
回答by Niko
If you don't want to use jQuery or PHP - can do next:
如果您不想使用 jQuery 或 PHP - 可以执行以下操作：
- Give ID or different CLASS to each
<li>element in "your-include-nav.php". - Define the "active" style with CSS in
<head>section, on each page.
- 为
<li>“your-include-nav.php”中的每个元素提供ID 或不同的 CLASS 。 <head>在每个页面上的部分中使用 CSS 定义“活动”样式。
回答by Harshvardhan Singh Baghel
define variable $page="index.php" in index.php page and for other pages change the variable value according to the page name
在 index.php 页面中定义变量 $page="index.php" 其他页面根据页面名称更改变量值
<li class="<?php echo ($page == "index.php" ? "active" : "")?>">
<a href="index.php">Home</a>
</li>
<li class="<?php echo ($page == "about.php" ? "active" : "")?>">
<a href="about.php">About</a>
</li>
<li class="<?php echo ($page == "service.php" ? "active" : "")?>">
<a href="service.php">Services</a>
</li>
<li class="<?php echo ($page == "contact.php" ? "active" : "")?>">
<a href="contact.php">Contact</a>
</li>
回答by Hamza Khan
Add basename function. Then it will work i hope.
添加基名功能。然后它会起作用，我希望。
回答by Hamza Khan
Add basenamefunction before $_SERVER. I hope it will work.
basename之前添加功能$_SERVER。我希望它会起作用。
echo (basename($_SERVER['PHP_SELF']) == 'yourPageName' ?'active' : " ");
回答by Alexander Zemskov
$page_url = $_SERVER['QUERY_STRING'];
$s = explode("&",$page_url);
//print $s[0];
$page = $s[0];
function createTopNav($page)
{
$pages = array(
array(
'name'=>'Feeder',
'link'=>'page=feeder'
),
array(
'name'=>'Services',
'link'=>'page=services'
),
array(
'name'=>'Development',
'link'=>'page=development'
),
array(
'name'=>'Design',
'link'=>'page=design'
),
);
$res = "";
foreach($pages as $key=>$val)
{
if($val['link']==$page)
{
$res.= "<a class=\"active\" href=\"?"
.$val['link'].
"\">"
.$val['name'].
"</a>";
}
else
{
$res.= "<a class=\"\" href=\"?"
.$val['link'].
"\" >"
.$val['name'].
"</a>";
}
}
$res.="";
return $res;
}
echo createTopNav($page);
回答by Punit
if you are using query string exmaple.com?page_id=Appsto pass page id than with php you can
approach this thing
如果您使用查询字符串exmaple.com?page_id=Apps来传递页面 id 而不是使用 php，您可以处理这个问题
$page_id = $_REQUEST['page_id'];
$page_id = $_REQUEST['page_id'];
<ul>
<li class="<?php echo ($page_id == "Home" ? "active" : "");?>">
<a href="/">Home</a>
</li>
<li class="<?php echo ($page_id == "Apps" ? "active" : "");?>">
<a href="#">Apps</a>
</li>
<li class="<?php echo ($page_id == "Forums" ? "active" : ""); ?>">
<a href="#">Forums</a>
</li>
</ul>
回答by lightofsouls
At page header use:
在页眉使用：
<?php $loc = this.location; ?>
Then at every link add:
然后在每个链接添加：
<?php(this.href == $loc) ? echo 'class="active"' : '' ?>
